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anonymous

  • one year ago

This is bothering me. Should the answer be y=-x+3 because the slope is going down down three and over to the left three meaning it'll be -3/3=-1 aka -x? Here is the graph: http://i.imgur.com/EvrzW1I.png

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  1. jim_thompson5910
    • one year ago
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    |dw:1436593889252:dw|

  2. jim_thompson5910
    • one year ago
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    |dw:1436593898587:dw|

  3. jim_thompson5910
    • one year ago
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    negative slopes look like this |dw:1436593957282:dw|

  4. anonymous
    • one year ago
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    I thought I had to go up three because of the y-int and then come down from there

  5. jim_thompson5910
    • one year ago
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    that +3 is where you start on the y axis you go up 1, to the right 1 to jump to the next point the slope is actually +1 and not -1

  6. anonymous
    • one year ago
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    Hmm alright. Well thank you very much! Have a good night!

  7. jim_thompson5910
    • one year ago
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    slope = rise/run = 1/1 = 1 |dw:1436594102303:dw|

  8. jim_thompson5910
    • one year ago
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    no problem

  9. anonymous
    • one year ago
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    Hold on

  10. anonymous
    • one year ago
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    So I don't have to start at that +3?

  11. anonymous
    • one year ago
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    I start at the -3 on the X axis?

  12. jim_thompson5910
    • one year ago
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    you start at (0,3) which is +3 on the y axis (the vertical axis)

  13. jim_thompson5910
    • one year ago
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    |dw:1436594256975:dw|

  14. anonymous
    • one year ago
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    and the do I go down one down and one over from there?

  15. jim_thompson5910
    • one year ago
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    always move from left to right we move 1 unit up (rise) and 1 unit to the right (run) which is why slope = rise/run = 1/1 = 1

  16. anonymous
    • one year ago
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    OOOOOOOH

  17. anonymous
    • one year ago
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    I have to go up not down - I feel dub now xD

  18. jim_thompson5910
    • one year ago
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    well you only go down if the slope happened to be negative

  19. anonymous
    • one year ago
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    Thank you! This time for real (:

  20. jim_thompson5910
    • one year ago
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    you're welcome

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