vera_ewing
  • vera_ewing
Math question
Mathematics
schrodinger
  • schrodinger
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vera_ewing
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vera_ewing
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vera_ewing
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vera_ewing
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Michele_Laino
  • Michele_Laino
hint: we can write this identity: \[\Large {\log _6}12 = \frac{{{{\log }_{10}}12}}{{{{\log }_{10}}6}} = \frac{{{{\log }_{10}}6 + {{\log }_{10}}2}}{{{{\log }_{10}}6}} > 1\]
Michele_Laino
  • Michele_Laino
please, keep in mind that, the solution of your equation is: \[\Large y = {\log _6}12\]
vera_ewing
  • vera_ewing
So A is the answer right?
Michele_Laino
  • Michele_Laino
that's right!
vera_ewing
  • vera_ewing
Thanks, Michele!
Michele_Laino
  • Michele_Laino
:)

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