## anonymous one year ago Fan and Medal!!! What is the third term of a sequence that has a first term of 3 and a common ratio of 3? 1/3 9 27

1. welshfella

third term = a1 r^2 where a1 = first term , r = common ratio

2. anonymous

3*3^2 =9*3=27

3. anonymous

@welshfella is that right?

4. Michele_Laino

hint by definition of geometric sequence, we have: $\Large \begin{gathered} {a_1} = 3 \hfill \\ {a_2} = 3{a_1} = ... \hfill \\ {a_3} = 3{a_2} = ... \hfill \\ \end{gathered}$

5. welshfella

yes the nth term = a1 r^(n-1) here a1 = 3 and r = 3