anonymous
  • anonymous
Fan and Medal!!! What is the third term of a sequence that has a first term of 3 and a common ratio of 3? 1/3 9 27
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

welshfella
  • welshfella
third term = a1 r^2 where a1 = first term , r = common ratio
anonymous
  • anonymous
3*3^2 =9*3=27
anonymous
  • anonymous
@welshfella is that right?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Michele_Laino
  • Michele_Laino
hint by definition of geometric sequence, we have: \[\Large \begin{gathered} {a_1} = 3 \hfill \\ {a_2} = 3{a_1} = ... \hfill \\ {a_3} = 3{a_2} = ... \hfill \\ \end{gathered} \]
welshfella
  • welshfella
yes the nth term = a1 r^(n-1) here a1 = 3 and r = 3

Looking for something else?

Not the answer you are looking for? Search for more explanations.