## anonymous one year ago The region bounded below by the parabola y=x^2+4 and above by the line y=8 is partitioned into two subsections of equal area by cutting it across with the horizontal line y=c. Find C

1. anonymous

|dw:1436639110146:dw| there's symmetry about the y-axis, so $\int\limits_{0}^{\sqrt{c-4}}(c-(x^2+4))dx = \int\limits_{0}^{2}(8-c)dx$

2. anonymous

$(cx-\frac{ x^3 }{ 3 }-4x)|_{0}^{\sqrt{c-4}}=(8x-cx)|_{0}^{2}$

3. anonymous

anyone else?