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anonymous

  • one year ago

The region bounded below by the parabola y=x^2+4 and above by the line y=8 is partitioned into two subsections of equal area by cutting it across with the horizontal line y=c. Find C

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  1. anonymous
    • one year ago
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    |dw:1436639110146:dw| there's symmetry about the y-axis, so \[\int\limits_{0}^{\sqrt{c-4}}(c-(x^2+4))dx = \int\limits_{0}^{2}(8-c)dx\]

  2. anonymous
    • one year ago
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    \[(cx-\frac{ x^3 }{ 3 }-4x)|_{0}^{\sqrt{c-4}}=(8x-cx)|_{0}^{2}\]

  3. anonymous
    • one year ago
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    anyone else?

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