A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Can someone please check my work on this equation so far? Here is the question...
Two point charges each carrying a charge of + 4.5 E – 6 C are located 4.5 meters away from each other. How strong is the electrostatic force between the two points and is this force a repulsive force or an attractive force (k = 9.0 E9 Nm2/C2)?
So the values I have are as follows...
F = ?
k = 9.0 E9 Nm^2/C^2
q1 = 4.5 E  6 C
q2 = 4.5 E  6 C
r = 4.5 m
Am I on the right track? Thanks!
anonymous
 one year ago
Can someone please check my work on this equation so far? Here is the question... Two point charges each carrying a charge of + 4.5 E – 6 C are located 4.5 meters away from each other. How strong is the electrostatic force between the two points and is this force a repulsive force or an attractive force (k = 9.0 E9 Nm2/C2)? So the values I have are as follows... F = ? k = 9.0 E9 Nm^2/C^2 q1 = 4.5 E  6 C q2 = 4.5 E  6 C r = 4.5 m Am I on the right track? Thanks!

This Question is Closed

ash2326
 one year ago
Best ResponseYou've already chosen the best response.1@SarahCatherinez yes you have got the values of each of the parameter correct. Seem to be on the right track. Go on and plug in the values in the formula for force.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Great! I'll go ahead and plug in the values, if you wouldn't mind checking my work from there.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0F = (9.0 E9) * (4.5 E 6) * (4.5 E 6)/(4.5^2) F = (9.0 E9) * (4.5 E 6) * (4.5 E 6)/(20.25) F = (9.0 E9) * (4.5 E 6) * (2.2 E 7) F = .00891 N

ash2326
 one year ago
Best ResponseYou've already chosen the best response.1There seems to be a mistake in 3rd step.Could you check?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hm, that's odd. I just entered it into my calculator and got the same answer.

ash2326
 one year ago
Best ResponseYou've already chosen the best response.1yes, sorry. Your answer is close to the correct. I would show you another way you have this \[F=\frac{9*10^9*(4.5 *10^{6})^2}{4.5^2}\] \[F=\frac{9*10^9*(4.5)^2 *(10^{6})^2}{4.5^2}\] \[F=\frac{9*10^9*\cancel{(4.5)^2} *(10^{6})^2}{\cancel{4.5^2}}\] \[F=9*10^9*10^{12} N\] Do you follow this method?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh yes, that makes sense.

ash2326
 one year ago
Best ResponseYou've already chosen the best response.1I think you can find the answer now, can't you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I believe so. Thank you so much for your help! :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.