log 100.1=?

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log 100.1=?

Linear Algebra
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[\log_{10}(100.1)\]?
is what @UnkleRhaukus asked
yea

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actually the base is not given. if this case happens which base we have to take. or do without taking base?
i have done, log 1001/10 => log1001-log10 => log1001 - 1
seems good,
i would of used base 10 in this case like you did that's why log10=1
oke *_* thanx but how to break log 1001
log1001 = 3(approx.)
you want to write in simplest forms? i was thing of 11x91 but that is not of any good i guess
so my ans wud be 3-1=2
no not really
yep! approx. 2
:) cool
log1001-1=log11+log91-1 ====================== i don't you are looking for an approximation do u? unless the questionm asked that
no no not approx
just keep things compound when the question does not mention estimate or approx
i will prefer if exact ans do comes
then don't go by that approx the fellow suggested
i ment compact not compound! lol
ok sir
you're right @xapproachesinfinity . it depend on what question says.
unless you can break down log1001 to a more compact form then just leave as it is
fine .but it is going very lengthy .
if we solve by 11*91
does not matter! is just depend what the question requires you to do
i said earlier that does not help i just mentioned that i was thing that way but not of any hope it would be good
thinking*
first step of problem solving _ 1- Understanding problem/question (from, How to solve it-George Polya).
yep ! thnx all
you are new to open study i guess!
yes

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