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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[2x^3+ 5x^2 1 \le 0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0solve the inequality

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2what course are you taking! now of some factoring thoerems

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2i meant do you know of some factoring theorems or not

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2\(2x^3+5x^21=0\) has one solution we start by factoring this equation first so we can draw conclusion about the inequality

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i found a factor but don't know how to continue.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436640267462:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The course I am currently taking is precalc @xapproachesinfinity

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2oh good then what does it mean for ab<0

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2one has to be negative right? either a<0, b>0 or a>0, b<0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When ab multiply they must be less than zero?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2if it was numbers case if we multiply two negative give positive multiplying two positive return a positive so the remaining case is one negative the other positive

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes that is true so one of the variables has to be a negative

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2now we ask which should be positive and which negative so (x+1/2)<0 and the other>0 or (x+1/2)>0 and parabola<0

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2let's simplify first we can write it as (2x+1)(x^2+2x1)<=0

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2just hold on before that

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2can we look at that parabola first

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2x^2+2x1 can this be <0?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2if so when does it be <0 if not it must be >0 just the kind of thinking you need here okay

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2first that parabola opens up yes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes it does with minimum (1,2)

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2here is a picture of that parabola http://prntscr.com/7rixyx

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2so it has part where it is <0 and as well as part where it is >0 good enough

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2not really f(x)<0 when x1<x<x2 x1,x2 are root of x^2+2x1

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2there are irrational roots

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2and f(x)>0 for x<x1 and x>x2

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2you got that part?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2let's go back with the first step (2x+1)(x^2+2x1)<=0 implies 2x+1> 0 and x^2+2x1<0 first case

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2we solve for that case by itself!

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2second case (2x+1)<0 and (x^2+2x1)>0

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2we already decided when x^2+2x+1<=0 and when x^2+2x1>=0 just a matter of solving 2x+1<0 2x+1>0 then combine

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2or means union

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2you got it now?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2let see the first case 2x+1>0 and x^2+2x1<0 x>1/2 and x in [x1,x2] well you still need to decide what is x1 and x2 though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the final answer would be dw:1436641853588:dw

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2hm where did you [1.0] i said x1 and x2 are not 1 and 0

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2and what 3 there? you have to explain your work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436641991554:dw

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2roots are x1=1root2 , x2=root21

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436642079744:dw

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2so first case is x>=1/2 and 1root2<=x<=root21

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2coming back i have a call

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes that is correct so i just need the roots of the second quadratic

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436642261054:dw

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2intersection here not union

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2root2 not root6

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2union is the last step

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so how would the final answer look like?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2i don;t know yet, i'm doing with you lol

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2so we have first case (oo, 1/2] with [x1, x2] can you find that interval what is ?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2do number line

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(oo, 3.44) U (1/2, 1.44]

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2oh wait a minute error you would have (1/2, oo) not oo, 1/2 first case! look above

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2(1/2,oo) intersection with [3.4, 1.4]

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2so that would be [1/2, 1.44]

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2that's what they share

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2now second case x<1/2 and x<3.44 and x>1.44

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2(oo, 0.5) intersect (oo,3.44) intersect (1.44, oo)

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2you there?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2i think we don't need [1.4, oo) there not intersection with that part

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2just (oo, 0.5] and (oo, 3.4] find the interval of intersection

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2you lost ? lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just on whether its a union or a intersection
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