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cud anybody give me the full solution. ?

since \[\log(p+q)(p-q) = -1\]
so \[\log(p+q) -1 =0\]

log(p^2-q^2) = log(p+q)(p-q) = -1
but i cant see a way to find what log(p+q) is.

@welshfella that's in my last reply

log(p+q) = 1

so since log(p+q) = 1
it will be:
\[\log(p+q)\log(p^2-q^2) = 0\]

i cant see your logic there - I'm not saying you are wrong

if log ( p + q) = 1
log(p+q)log(p^-q^2) = 1 * -1 = -1 not 0

oh yes my bad I was subtracting
then yes it would be -1

can the asker post the screenshot of the question?

but isn't it
log(a*b) = log(a) + log(b)?

yes that is true

that is the product rule for log

yeah its d

yes - that is correct - we need more info to get a definitive answer.

yes

and what wud be the answer in this case , 1 or 2?

no way to tell

Not enough info is given to apply one of the choices

but it seems good

we are not given with any base , so we have to identify by ourself that the base is given or not

that is not ryt

what are you talking about?

the answer?

I didn't give an answer to your problem

the above way that you have used to solve the question

taking base p+q

fine

answer is that, the question doesnt make any sense,. lol