anonymous
  • anonymous
can someone help me please?:)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
1 Attachment
xapproachesinfinity
  • xapproachesinfinity
1 step is okay yes we can square root both sides no problem right?
anonymous
  • anonymous
sure

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xapproachesinfinity
  • xapproachesinfinity
oh that's second step not first
xapproachesinfinity
  • xapproachesinfinity
first is just equation itself
anonymous
  • anonymous
yea
xapproachesinfinity
  • xapproachesinfinity
so 1 and 2 no problem
hba
  • hba
Do you think there is a fault in the 3rd step?
xapproachesinfinity
  • xapproachesinfinity
3 now what do you think
xapproachesinfinity
  • xapproachesinfinity
look at one side of the equation at a time
anonymous
  • anonymous
sorry, my laptop is lagging,and it step 3 looks fine to me:S
xapproachesinfinity
  • xapproachesinfinity
hehe can we do this \(\sqrt{a^2+b^2}=a+b?\)
anonymous
  • anonymous
i guess not lol
hba
  • hba
Well as @xapproachesinfinity said the R.H.S is fine as \[\sqrt{c^2} = c \] as they cancel
xapproachesinfinity
  • xapproachesinfinity
yes it is not allowed
anonymous
  • anonymous
rhs?
hba
  • hba
But it should be something like \[\sqrt{(a+b)^2}\] to become a+b
xapproachesinfinity
  • xapproachesinfinity
right hand side :)
hba
  • hba
So to get that we know that we want something like \[\sqrt{a^2+2ab+b^2}\]
xapproachesinfinity
  • xapproachesinfinity
for this \(\sqrt{b^2+a^2}\) we cannot do anything to it
hba
  • hba
We cannot? :o
xapproachesinfinity
  • xapproachesinfinity
yes we can't as far as the problem is concerned!
hba
  • hba
We can solve it by adding root(2ab) on both sides?
anonymous
  • anonymous
im confused lol
xapproachesinfinity
  • xapproachesinfinity
hmm you meant \(|c|+\sqrt{2ab}=\sqrt{a^2+b^2}+\sqrt{2ab }\)
xapproachesinfinity
  • xapproachesinfinity
is that what you saying ?
hba
  • hba
No that won't do but we can add something to it so it becomes root(a^2+b^2+2ab)
xapproachesinfinity
  • xapproachesinfinity
you can't you add 2ab under the root so you must subtract it under the root
hba
  • hba
Well we shouldn't had done this step in the first place lol :p
xapproachesinfinity
  • xapproachesinfinity
this problem we need to go back to a^2+b^2=c^2 solve a a^2=c^2-b^2 take root root(a^2)=root(c^2-b^2) |a|=root(c^2-b^2) a=+-root(c^2-b^2) the correct approach
hba
  • hba
We could have done something like a^2 = c^2 - b^2 so we'd get a= root(c^2-b^2) for an answer
hba
  • hba
Lol we just wrote the samething
xapproachesinfinity
  • xapproachesinfinity
yeah true
xapproachesinfinity
  • xapproachesinfinity
but we need +- too
anonymous
  • anonymous
:S
hba
  • hba
Agreed
hba
  • hba
But the ques says +
xapproachesinfinity
  • xapproachesinfinity
eh i didn;t read that positive reals part lol
xapproachesinfinity
  • xapproachesinfinity
so it has to be a=root(c^2-b^2)
anonymous
  • anonymous
yall are arguing a question which you both know but are not helping the actual person who needs help, both of u just completly confused me
hba
  • hba
@Sammii09 LoL
xapproachesinfinity
  • xapproachesinfinity
ok now we need to promptly do this problem first step checked second step no we need to solve for a^2 third step square rroot both sides 4th step a=... that is it
hba
  • hba
I'm just gonna leave @xapproachesinfinity is here
xapproachesinfinity
  • xapproachesinfinity
haha lol @Sammii09
xapproachesinfinity
  • xapproachesinfinity
look at my comment before this i did the problem
anonymous
  • anonymous
ok
xapproachesinfinity
  • xapproachesinfinity
first step is okay 2 step no ( we need to isolate a^2 in one side) 3 step (no that's not allowed) (suggest take square root of both side of this equation a^2=c^2-b^2) 4 step no (since third is wrong 4 will also be wrong) (suggested a=root(c^2-b^2)) done!
anonymous
  • anonymous
okay thanks
xapproachesinfinity
  • xapproachesinfinity
no problem

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