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anonymous

  • one year ago

can someone help me please?:)

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  1. anonymous
    • one year ago
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  2. xapproachesinfinity
    • one year ago
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    1 step is okay yes we can square root both sides no problem right?

  3. anonymous
    • one year ago
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    sure

  4. xapproachesinfinity
    • one year ago
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    oh that's second step not first

  5. xapproachesinfinity
    • one year ago
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    first is just equation itself

  6. anonymous
    • one year ago
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    yea

  7. xapproachesinfinity
    • one year ago
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    so 1 and 2 no problem

  8. hba
    • one year ago
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    Do you think there is a fault in the 3rd step?

  9. xapproachesinfinity
    • one year ago
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    3 now what do you think

  10. xapproachesinfinity
    • one year ago
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    look at one side of the equation at a time

  11. anonymous
    • one year ago
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    sorry, my laptop is lagging,and it step 3 looks fine to me:S

  12. xapproachesinfinity
    • one year ago
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    hehe can we do this \(\sqrt{a^2+b^2}=a+b?\)

  13. anonymous
    • one year ago
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    i guess not lol

  14. hba
    • one year ago
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    Well as @xapproachesinfinity said the R.H.S is fine as \[\sqrt{c^2} = c \] as they cancel

  15. xapproachesinfinity
    • one year ago
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    yes it is not allowed

  16. anonymous
    • one year ago
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    rhs?

  17. hba
    • one year ago
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    But it should be something like \[\sqrt{(a+b)^2}\] to become a+b

  18. xapproachesinfinity
    • one year ago
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    right hand side :)

  19. hba
    • one year ago
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    So to get that we know that we want something like \[\sqrt{a^2+2ab+b^2}\]

  20. xapproachesinfinity
    • one year ago
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    for this \(\sqrt{b^2+a^2}\) we cannot do anything to it

  21. hba
    • one year ago
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    We cannot? :o

  22. xapproachesinfinity
    • one year ago
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    yes we can't as far as the problem is concerned!

  23. hba
    • one year ago
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    We can solve it by adding root(2ab) on both sides?

  24. anonymous
    • one year ago
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    im confused lol

  25. xapproachesinfinity
    • one year ago
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    hmm you meant \(|c|+\sqrt{2ab}=\sqrt{a^2+b^2}+\sqrt{2ab }\)

  26. xapproachesinfinity
    • one year ago
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    is that what you saying ?

  27. hba
    • one year ago
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    No that won't do but we can add something to it so it becomes root(a^2+b^2+2ab)

  28. xapproachesinfinity
    • one year ago
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    you can't you add 2ab under the root so you must subtract it under the root

  29. hba
    • one year ago
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    Well we shouldn't had done this step in the first place lol :p

  30. xapproachesinfinity
    • one year ago
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    this problem we need to go back to a^2+b^2=c^2 solve a a^2=c^2-b^2 take root root(a^2)=root(c^2-b^2) |a|=root(c^2-b^2) a=+-root(c^2-b^2) the correct approach

  31. hba
    • one year ago
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    We could have done something like a^2 = c^2 - b^2 so we'd get a= root(c^2-b^2) for an answer

  32. hba
    • one year ago
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    Lol we just wrote the samething

  33. xapproachesinfinity
    • one year ago
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    yeah true

  34. xapproachesinfinity
    • one year ago
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    but we need +- too

  35. anonymous
    • one year ago
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    :S

  36. hba
    • one year ago
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    Agreed

  37. hba
    • one year ago
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    But the ques says +

  38. xapproachesinfinity
    • one year ago
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    eh i didn;t read that positive reals part lol

  39. xapproachesinfinity
    • one year ago
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    so it has to be a=root(c^2-b^2)

  40. anonymous
    • one year ago
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    yall are arguing a question which you both know but are not helping the actual person who needs help, both of u just completly confused me

  41. hba
    • one year ago
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    @Sammii09 LoL

  42. xapproachesinfinity
    • one year ago
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    ok now we need to promptly do this problem first step checked second step no we need to solve for a^2 third step square rroot both sides 4th step a=... that is it

  43. hba
    • one year ago
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    I'm just gonna leave @xapproachesinfinity is here

  44. xapproachesinfinity
    • one year ago
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    haha lol @Sammii09

  45. xapproachesinfinity
    • one year ago
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    look at my comment before this i did the problem

  46. anonymous
    • one year ago
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    ok

  47. xapproachesinfinity
    • one year ago
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    first step is okay 2 step no ( we need to isolate a^2 in one side) 3 step (no that's not allowed) (suggest take square root of both side of this equation a^2=c^2-b^2) 4 step no (since third is wrong 4 will also be wrong) (suggested a=root(c^2-b^2)) done!

  48. anonymous
    • one year ago
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    okay thanks

  49. xapproachesinfinity
    • one year ago
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    no problem

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