can someone help me please?:)

- anonymous

can someone help me please?:)

- katieb

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- anonymous

##### 1 Attachment

- xapproachesinfinity

1 step is okay yes
we can square root both sides no problem right?

- anonymous

sure

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## More answers

- xapproachesinfinity

oh that's second step not first

- xapproachesinfinity

first is just equation itself

- anonymous

yea

- xapproachesinfinity

so 1 and 2 no problem

- hba

Do you think there is a fault in the 3rd step?

- xapproachesinfinity

3 now what do you think

- xapproachesinfinity

look at one side of the equation at a time

- anonymous

sorry, my laptop is lagging,and it step 3 looks fine to me:S

- xapproachesinfinity

hehe can we do this \(\sqrt{a^2+b^2}=a+b?\)

- anonymous

i guess not lol

- hba

Well as @xapproachesinfinity said the R.H.S is fine as \[\sqrt{c^2} = c \] as they cancel

- xapproachesinfinity

yes it is not allowed

- anonymous

rhs?

- hba

But it should be something like \[\sqrt{(a+b)^2}\] to become a+b

- xapproachesinfinity

right hand side :)

- hba

So to get that we know that we want something like \[\sqrt{a^2+2ab+b^2}\]

- xapproachesinfinity

for this \(\sqrt{b^2+a^2}\) we cannot do anything to it

- hba

We cannot? :o

- xapproachesinfinity

yes we can't as far as the problem is concerned!

- hba

We can solve it by adding root(2ab) on both sides?

- anonymous

im confused lol

- xapproachesinfinity

hmm you meant \(|c|+\sqrt{2ab}=\sqrt{a^2+b^2}+\sqrt{2ab }\)

- xapproachesinfinity

is that what you saying ?

- hba

No that won't do but we can add something to it so it becomes root(a^2+b^2+2ab)

- xapproachesinfinity

you can't you add 2ab under the root so you must subtract it under the root

- hba

Well we shouldn't had done this step in the first place lol :p

- xapproachesinfinity

this problem we need to go back to a^2+b^2=c^2
solve a
a^2=c^2-b^2
take root
root(a^2)=root(c^2-b^2)
|a|=root(c^2-b^2)
a=+-root(c^2-b^2) the correct approach

- hba

We could have done something like
a^2 = c^2 - b^2
so we'd get
a= root(c^2-b^2) for an answer

- hba

Lol we just wrote the samething

- xapproachesinfinity

yeah true

- xapproachesinfinity

but we need +- too

- anonymous

:S

- hba

Agreed

- hba

But the ques says +

- xapproachesinfinity

eh i didn;t read that positive reals part lol

- xapproachesinfinity

so it has to be a=root(c^2-b^2)

- anonymous

yall are arguing a question which you both know but are not helping the actual person who needs help, both of u just completly confused me

- hba

@Sammii09 LoL

- xapproachesinfinity

ok now we need to promptly do this problem
first step checked
second step no we need to solve for a^2
third step square rroot both sides
4th step a=... that is it

- hba

I'm just gonna leave @xapproachesinfinity is here

- xapproachesinfinity

haha lol @Sammii09

- xapproachesinfinity

look at my comment before this
i did the problem

- anonymous

ok

- xapproachesinfinity

first step is okay
2 step no ( we need to isolate a^2 in one side)
3 step (no that's not allowed) (suggest take square root of both side of this equation
a^2=c^2-b^2)
4 step no (since third is wrong 4 will also be wrong) (suggested a=root(c^2-b^2))
done!

- anonymous

okay thanks

- xapproachesinfinity

no problem

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