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pandaecat

  • one year ago

A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the rectangle. A 3 to the 2 over 3 power inches squared B 3 to the 8 over 3 power inches squared C 9 inches squared D9 to the 2 over 3 power inches squared I think it's C but I'm not really sure. Can someone explain to me?

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  1. egbeach
    • one year ago
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    the formula for area is length x width

  2. pandaecat
    • one year ago
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    @egbeach I know that... but I just don't get how u simply the thing

  3. egbeach
    • one year ago
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    \[\sqrt[3]{81} \times 3^{\frac{ 2 }{ 3 }}\]

  4. egbeach
    • one year ago
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    thats the equation right?

  5. pandaecat
    • one year ago
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    Yes

  6. egbeach
    • one year ago
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    well whats \[\sqrt[3]{81}\]

  7. pandaecat
    • one year ago
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    81 and one third

  8. egbeach
    • one year ago
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    \[81^{\frac{ 1 }{ 3}}\times 3^{\frac{ 2 }{ 3}}\]

  9. egbeach
    • one year ago
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    are you able to solve that?

  10. pandaecat
    • one year ago
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    Um er a moment

  11. egbeach
    • one year ago
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    it should work if you plug it into a calculator correctly

  12. pandaecat
    • one year ago
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    54???

  13. egbeach
    • one year ago
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    ummm no... the answer is actually 9 so you were right

  14. pandaecat
    • one year ago
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    Oh then... I'll check again... Just confused

  15. egbeach
    • one year ago
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    ok

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