If 4.2 moles of copper metal reacts with 6.3 moles of silver nitrate, how many moles of silver metal can be formed, and how many moles of the excess reactant will be left over when the reaction is complete? Unbalanced equation: Cu + AgNO3 → Cu(NO3)2 + Ag Be sure to show all of your work. @taramgrant0543664 @photon336

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

If 4.2 moles of copper metal reacts with 6.3 moles of silver nitrate, how many moles of silver metal can be formed, and how many moles of the excess reactant will be left over when the reaction is complete? Unbalanced equation: Cu + AgNO3 → Cu(NO3)2 + Ag Be sure to show all of your work. @taramgrant0543664 @photon336

Chemistry
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

xCu + 2xAgNO3 --> xCu(NO3)2 + 2xAg If 2X=6.3, find X and hence no of moles reacted nd unreacted
Huh?
Here AgNO3 is the limiting reagent, so you have to calculate based on it

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Can you walk me through this whole equation because it's so confusing
The balanced eqn says that 1 mole of Cu requires 2 moles of AgNO3 to react with it. Since, you have 4.2 moles of Cu metal, it means you require 8.4 moles of AgNO3, which you don't have. So, you have to consider that you have 6.3 moles of AgNO3 that reacts with 6.3/2 moles(=3.15 moles) of Cu. So, no of moles of Ag formed=6.3 moles and, no of moles of unreacted Cu=4.2-3.15=1.05 moles
Whats the balanced equation?
Cu + 2AgNO3 --> Cu(NO3)2 + 2Ag
Ok then what?
The balanced eqn says that 1 mole of Cu requires 2 moles of AgNO3 to react with it. Since, you have 4.2 moles of Cu metal, it means you require 8.4 moles of AgNO3, which you don't have. So, you have to consider that you have 6.3 moles of AgNO3 that reacts with 6.3/2 moles(=3.15 moles) of Cu. So, no of moles of Ag formed=6.3 moles and, no of moles of unreacted Cu=4.2-3.15=1.05 moles

Not the answer you are looking for?

Search for more explanations.

Ask your own question