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anonymous
 one year ago
Find volume of solid generated
anonymous
 one year ago
Find volume of solid generated

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436654820728:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand the infinity part on the left side if it isn't enclosed from there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oops sorry i was looking at the wrong part XD

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436654961888:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure what that is, but that is not even close. Thank you though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it is ln15e^(ln15)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you have the area of the box ln15*1  pi integral(e^(x/2)^2)dx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the integral is just pi*integra(e^x)=pi*e^x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you as well, but no

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436655396490:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Your drawing is incorrect as well. I do appreciate the help, but its not helping

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0forgot the triangle bit thing with the curvy roof

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, it is bounded bounded by 1 you have it bounded by y=0

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1V = pi(e^(ln15)  e^0)  ln15 pi = 14pi  ln15pi = 11.29 pi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[V=\ln15\int\limits_{0}^{\ln15}y^2dx\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0YES How did you get that I couldn't make out what yo had up top

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0mathway.com for graphing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thta was to welshfella

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1the diagram you mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no the answer its pi(14ln15)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did you derive that i forgot to add that its supposed to be the shell method, but I'm not too concerned with that

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436655815791:dw

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1the shaded area is rotated about x axis so we need the volume of the area down to the x axis minus the area of the cylinder below

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not doing very well... i kept thinking it was a square and forgot it had to be revolved into a cylinder...

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436655967976:dw

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1that gives volume of revolution of the shaded area below dw:1436656237239:dw

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1 then you need to subtract the volume of the cylinder radius 1 and length ln15

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1yw as for the 'shell method' i dont know what that is ( i cant remember that in school  mind that was a long time ago)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its 2pi integral (shell height)(shell radius)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1ah i see  the method i used was integrating infinitely thin discs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah the shell is integrating "coffee cans"
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