A community for students.
Here's the question you clicked on:
 0 viewing
LynFran
 one year ago
Help...
LynFran
 one year ago
Help...

This Question is Closed

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\mathrm{Find\:the\:equivalent\:expressions\:\to\:}\left2x3\right\mathrm{\:at\:}1\le \:x\le \:2\mathrm{\:without\:the\:absolutes}\] \[1\le \:x\le \frac{3}{2}:\quad \left(32x\right)\] \[\frac{3}{2}\le \:x\le \:2:\quad \left(2x3\right)\] \[=\int\limits _{1}^{\frac{3}{2}}\left(32x\right)dx+\int\limits _{\frac{3}{2}}^2\left(2x3\right)dx\] \[\int\limits _{1}^{\frac{3}{2}}\left(32x\right)dx=\frac{25}{4}\] \[\int\limits _{\frac{3}{2}}^2\left(2x3\right)dx=\frac{1}{4}\] \[=\frac{25}{4}+\frac{1}{4}\] \[=\frac{13}{2}\] Answer is.. \[\frac{13}{2}\quad \left(\mathrm{Decimal:\quad }\:6.5\right)\]

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0any confusion @LynFran

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1ok i know the answer is 13/2...but i have to use a method from geometry ...? im confuse...

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1@TheSmartOne @abb0t @sleepyhead314

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0I don't know the geometry method.. I would've done the same thing as @DecentNabeel

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.22x3 is an absolute value function which when you graph looks like a V you would graph it then us the triangle formula

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.21/2 base times height

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0yes absolute value graphs have a V shape. ^ :)

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2would have to break into two triangles

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1so how do i graph it...do i need to input the lower and upper limits to get the function..im still confuse..

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2dw:1436662192706:dw

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2dw:1436662409249:dw

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2we can get two triangles one with a base of (1.5 + 1) and height of 5 another with a base of (2  1.5) and height of 1

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2sorry that my drawing is not really scaled ^_^"

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1where did u get those points from? dw:1436669704611:dw

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2by graphing... y = 2x  3 y intercept is "3" coming out of absolute value +3 x intercept is 1.5 find the points given by bounds when x = 1 > y = 5 when x = 2 > y = 1

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2you have learned how to graph absolute value functions before... right? oo (i mean, if you're learning calculus, I'm assuming you know how)

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1so i dont need to input the upper and lower limits in 2x3...thats what im not clear no...

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2naaa you just need to be able to visualize it dw:1436662834072:dwhere are the bounds

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2here are the triangles you need to find the geometric areas of dw:1436662904906:dw

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2need me to go further or you got it?

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.2back to sleep then have fun zzzzzzzzzzzzzzzzzzzz

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1no wait..look at this one how they get those coordinate for that sketch ?..didnt they input the limit to get it? https://www.symbolab.com/solver/calculuscalculator/%5Cint_%7B1%7D%5E%7B4%7Dx%20dx%20/?origin=enterkey @sleepyhead314
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.