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Destinyyyy
 one year ago
perform the addition.. How do I solve this? The answer I got was incorrect.
Destinyyyy
 one year ago
perform the addition.. How do I solve this? The answer I got was incorrect.

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Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Yes I know that thats the correct answer. Im not asking for that. Im asking how to solve it

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\left(5i5\right)+\left(8i+9\right)\] \[\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\] \[=\left(5i5\right)+8i+9\] \[\mathrm{Add/Subtract\:the\:numbers:}\:5+9=4\] \[=8i+5i+4\] \[\mathrm{Add\:similar\:elements:}\:8i+5i=13i\] \[=13i+4\] that is the answer

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0are you understand @Destinyyyy

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Sorry one second while I read it.. There was a spider in my room :(

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0hahaha no problem @Destinyyyy

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1My example said to remove the i and put it outside of the equation.. (5 +5) +(9+8)i

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1It was fluttering huge... Death by broom

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1it change fing to fluttering .

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\mathrm{Simplify}\:\left(5+5\right):\quad 0\] \[=i\left(8+9\right)+0\] \[\mathrm{Simplify}\:i\left(8+9\right):\quad 17i\] 17i+0=17i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The way your book does it is still true but i think its in this format (a+bi) + (d+ ci) = (a+d) (b+c) i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To add or subtract we use Add (a+bi) + (c +di) = (a+b) + (c +d)i Subtract (a+bi) (c +di) = (a+b)  (c +d)i So in your case (5+5i) + (9+8i) = (5+5) + (9+8)i 5+9 + 5+8 4 + 13i

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0any confusion @Destinyyyy

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0@Deeezzzz 5+9=4 not 4

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Okay.. I get it now.. I multiplied the parenthesis... Thank you everyone!!

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Yes.. Can I get help with another one?

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0yes tell me @Destinyyyy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks! @DecentNabeel simple arithmetic mistake

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0no problem @Deeezzzz

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Perform the addition (9/2 +1/2i) + (3/2  7/2i)

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\left(\frac{9}{2}+\frac{i}{2}\right)+\left(\frac{3}{2}\frac{7i}{2}\right)\] \[\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\] \[=\left(\frac{9}{2}+\frac{i}{2}\right)+\frac{3}{2}\frac{7i}{2}\] \[\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\] \[=\frac{7i+i+39}{2}\] refine \[=\frac{6i6}{2}\] factor out 6 \[=\frac{6\left(i+1\right)}{2}\] \[\mathrm{Divide\:the\:numbers:}\:\frac{6}{2}=3\] \[=\left(3\left(i+1\right)\right)\] \[\mathrm{Negate}\:\left(3\left(i+1\right)\right)=3\left(i+1\right)\] \[=3\left(i+1\right)\] that is the answer

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1??? Why is the 1 now i and the 7 now 7i?

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1My examples show to put the i on the outside of the equation like @Nixy did

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0why confused tell me

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0you said i on the out sides .. so that.. 3(i+1) =3i+3

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1No I mean like this (9/2 +1/2) + (3/2  7/2)i for the first step

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\] \[=\left(\frac{9}{2}+\frac{i}{2}\right)+\frac{3}{2}\frac{7i}{2}\]

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0alright @Destinyyyy

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1I dont understand why 1 is now i and why its 7i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\( \huge (\frac{9}{2} +\frac{1}{2}i) + (\frac{3}{2}  \frac{7}{2}i) \) Is the above how it looks in your book?

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0(9/2 +1/2i) + (3/2  7/2i) that is your question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\( \huge (\frac{9}{2} +\frac{1}{2}i) + (\frac{3}{2}  \frac{7}{2}i) \) \( \huge (\frac{9}{2} +\frac{1}{2}) + (\frac{3}{2}  \frac{7}{2}) i\) \( \huge (\frac{9}{2} +\frac{3}{2}) + (\frac{1}{2}  \frac{7}{2}) i\) \( \huge \frac{6}{2} + (\frac{6}{2}) i\) \( \huge 3 3i\)
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