lisa123
  • lisa123
solve for x. 4x^2=-13x-3
Mathematics
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lisa123
  • lisa123
solve for x. 4x^2=-13x-3
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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campbell_st
  • campbell_st
rewrite the problem as \[4x^2 + 13x + 3 = 0\] ' so to solve this I multiply 4 and 3 then find the factors that add to 13 any ideas..?
lisa123
  • lisa123
12 and 1
campbell_st
  • campbell_st
great so next write the factorisation as \[\frac{(4x + 12)(4x + 1)}{4}\] then remove the common factors from the numerators \[\frac{4(x + 3)(4x + 1)}{4} = 0\] cancel out the common factor in the numerator ad denominator then you can find the solutions

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lisa123
  • lisa123
so (x+3)(4x+1)
campbell_st
  • campbell_st
that's the factored for so you have x +3 = 0 or 4x + 1 = 0 so find the 2 values of x that make the equations true
lisa123
  • lisa123
-3 and -1/4
campbell_st
  • campbell_st
that's correct

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