## anonymous one year ago solve for x. 4x^2=-13x-3

1. campbell_st

rewrite the problem as $4x^2 + 13x + 3 = 0$ ' so to solve this I multiply 4 and 3 then find the factors that add to 13 any ideas..?

2. anonymous

12 and 1

3. campbell_st

great so next write the factorisation as $\frac{(4x + 12)(4x + 1)}{4}$ then remove the common factors from the numerators $\frac{4(x + 3)(4x + 1)}{4} = 0$ cancel out the common factor in the numerator ad denominator then you can find the solutions

4. anonymous

so (x+3)(4x+1)

5. campbell_st

that's the factored for so you have x +3 = 0 or 4x + 1 = 0 so find the 2 values of x that make the equations true

6. anonymous

-3 and -1/4

7. campbell_st

that's correct