Destinyyyy
  • Destinyyyy
Can someone explain these two problems to me...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Destinyyyy
  • Destinyyyy
Multiply and simplify answer. (5/3 +i)^2 I got 25/9 +10/3i+(-1) second problem- Divide 6+i/3-i
amoodarya
  • amoodarya
\[(\frac{5}{3 +i})^2\] do you mean ?
Destinyyyy
  • Destinyyyy
No (5/3 +i)^2

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More answers

Kash_TheSmartGuy
  • Kash_TheSmartGuy
\[(\frac{ 5 }{ 3 }+i)^{2}\]like this?
Destinyyyy
  • Destinyyyy
Yes
amoodarya
  • amoodarya
\[i^2=-1\\(\frac{5}{3} +i)^2=\\\frac{25}{9} +2(\frac{5}{3})(i) +i^2=\\\frac{25}{9}+\frac{10}{3}i -1\]
Destinyyyy
  • Destinyyyy
Yes I have that
amoodarya
  • amoodarya
\[\frac{6+i}{3-i}=\\\frac{6+i}{3-i}*\frac{3+i}{3+i}=\\=\frac{(6+i)(3+i)}{3^2-i^2}=\\\]can you go on ?
Destinyyyy
  • Destinyyyy
Wait so thats it for the first problem????
amoodarya
  • amoodarya
no , first is almost done just=st 25/9-1=(25-9)/9=16/9
Destinyyyy
  • Destinyyyy
??
amoodarya
  • amoodarya
25/9+10/3 i -1= 25/9-1 +10/3 i= 16/9 +10/3 i
Destinyyyy
  • Destinyyyy
So 16/9 + 10/3i is the final answer?
amoodarya
  • amoodarya
yes ,for 1st
Destinyyyy
  • Destinyyyy
Okay
amoodarya
  • amoodarya
do the second ?
Destinyyyy
  • Destinyyyy
Yes.. I have- 6+1/3-i * 3+i?3+i = 10+6i+3i+i^2/ 9+3i-3i-i^2 = 9+9i/10
amoodarya
  • amoodarya
\[\frac{ (6+i)(3+i) }{(3-i)(3+i) }=\frac{18+3i+6i+i^2}{9-(-1)}=\\frac{18-1+9i}{10}\]
amoodarya
  • amoodarya
18-1 +9i -------- 10
Destinyyyy
  • Destinyyyy
Where did you get the -1 for the top?
Destinyyyy
  • Destinyyyy
So the final answer is 17+9i/10 ??
amoodarya
  • amoodarya
yes
Destinyyyy
  • Destinyyyy
Alright.. Thank you.

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