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Destinyyyy
 one year ago
Can someone explain these two problems to me...
Destinyyyy
 one year ago
Can someone explain these two problems to me...

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Multiply and simplify answer. (5/3 +i)^2 I got 25/9 +10/3i+(1) second problem Divide 6+i/3i

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1\[(\frac{5}{3 +i})^2\] do you mean ?

Kash_TheSmartGuy
 one year ago
Best ResponseYou've already chosen the best response.0\[(\frac{ 5 }{ 3 }+i)^{2}\]like this?

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1\[i^2=1\\(\frac{5}{3} +i)^2=\\\frac{25}{9} +2(\frac{5}{3})(i) +i^2=\\\frac{25}{9}+\frac{10}{3}i 1\]

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{6+i}{3i}=\\\frac{6+i}{3i}*\frac{3+i}{3+i}=\\=\frac{(6+i)(3+i)}{3^2i^2}=\\\]can you go on ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait so thats it for the first problem????

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1no , first is almost done just=st 25/91=(259)/9=16/9

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.125/9+10/3 i 1= 25/91 +10/3 i= 16/9 +10/3 i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So 16/9 + 10/3i is the final answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes.. I have 6+1/3i * 3+i?3+i = 10+6i+3i+i^2/ 9+3i3ii^2 = 9+9i/10

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ (6+i)(3+i) }{(3i)(3+i) }=\frac{18+3i+6i+i^2}{9(1)}=\\frac{181+9i}{10}\]

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1181 +9i  10

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Where did you get the 1 for the top?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the final answer is 17+9i/10 ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright.. Thank you.
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