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anonymous
 one year ago
URGENT!!!: What is the range of f^1[g(x)]???
anonymous
 one year ago
URGENT!!!: What is the range of f^1[g(x)]???

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sammixboo
 one year ago
Best ResponseYou've already chosen the best response.1Maybe @triciaal or @jim_thompson5910 could help :)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1There seems to be missing information. Can you post a screenshot?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so this is all part of #6 and \[\Large f(x) = \frac{2}{x+3}\] \[\Large g(x) = 2^{x1}\] right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im stuck on part b). i have the domain i just cant figure out the range

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I agree that \[\Large f^{1}(x) = \frac{23x}{x}\] \[\Large f^{1}(g(x)) = \frac{23(2^{x1})}{2^{x1}}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you have the correct domain as well

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1as for the range, let me think

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large f^{1}(x) = \frac{23x}{x}\] \[\Large f^{1}(x) = \frac{2}{x}  \frac{3x}{x}\] \[\Large f^{1}(x) = \frac{2}{x}  3\] \[\Large f^{1}(g(x)) = \frac{2}{2^{x1}}  3\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1as x gets larger and larger, the term \(\LARGE \frac{2}{2^{x1}}\) gets smaller and smaller effectively getting to small that it becomes 0

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so as x gets larger and larger \[\Large f^{1}(g(x)) = \frac{2}{2^{x1}}  3\] gets closer and closer to 3. It will never actually get to 3 itself though

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1does that make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait so whats the range?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1if you plug in x = 0, what do you get?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large f^{1}(g(x)) = \frac{2}{2^{x1}}  3\] \[\Large f^{1}(g(0)) = \frac{2}{2^{01}}  3\] \[\Large f^{1}(g(0)) = ???\]

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0consider when x is negative when x = 0 and when x is positive

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0you said you had the actual domain the range is the set of y values

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can i pls just have the answer pls. this homework q is the last one and im rly tired plz

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0maybe infinity to 3 not sure

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1if you graph the entire thing, you'll get this

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1it goes up forever but doesn't do the same in the other direction. Instead it gets closer and closer to 3 (but never actually gets to 3) so the range is y > 3 which in interval notation is (3, infinity)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0omg thank you guys so much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i can finally sleep!!!!!

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0I see my error when x = infinity y is positive so the solution is like Jim has it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is anyone here still able to help me with one more q?
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