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anonymous
 one year ago
A ball is attached to a pole by a string. When the pole is rotating,
the distance from the center to the ball is 0.75 m. what is f net if the time for one revolution is 1.10 s and the mass is 2.6 kg? what is the length of the string?
anonymous
 one year ago
A ball is attached to a pole by a string. When the pole is rotating, the distance from the center to the ball is 0.75 m. what is f net if the time for one revolution is 1.10 s and the mass is 2.6 kg? what is the length of the string?

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shamim
 one year ago
Best ResponseYou've already chosen the best response.0So both forces on the ball is just oposit in direction and same magnitude

rajat97
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436676701741:dw Break the tension into two components the vertical will be Tcos(theta) and the horizontal component will be Tsin(theta). The vertical component will cancel the gravitational force mg and the horizontal will provide the centripetal force. so you get, Tcos(theta)=mg and Tsin(theta)=(mv^2)/r here r=0.75m divide both the equations and you'll get tan(theta) now you can find sin(theta) from tan(theta) and hence find the length of the string that is the hypotenuse. I think this helps you

rajat97
 one year ago
Best ResponseYou've already chosen the best response.1ps. theta is the angle between the string and the poledw:1436678756598:dw
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