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anonymous
 one year ago
there are 40 beads.
7/40 are yellow
5/40 are green
9/40 are blue
8/40 are brown
7/40 are orange
4/40 are red
calculate WITH replacement and WITHOUT replacement for each:
P(R1B2 OR B1R2)
P(R1 AND G2)
P(no yellows)
P(doubles)
P(no doubles)
anonymous
 one year ago
there are 40 beads. 7/40 are yellow 5/40 are green 9/40 are blue 8/40 are brown 7/40 are orange 4/40 are red calculate WITH replacement and WITHOUT replacement for each: P(R1B2 OR B1R2) P(R1 AND G2) P(no yellows) P(doubles) P(no doubles)

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nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0where is your attempt?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay so for the or situation would it be like 2/1600 + 2/1600

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436673083490:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0are we considering only exactly as written in that order 1 red then 2 green or do you need any combination of 1 red and 2 green ?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436673692973:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0can you clarify P(doubles) and P(no doubles) how many are you getting?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436674059198:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0with replacement means you are putting the chosen bead back in the "pool" before picking again. without replacement means you have one less each time you pull one bead out the group.
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