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anonymous

  • one year ago

there are 40 beads. 7/40 are yellow 5/40 are green 9/40 are blue 8/40 are brown 7/40 are orange 4/40 are red calculate WITH replacement and WITHOUT replacement for each: P(R1B2 OR B1R2) P(R1 AND G2) P(no yellows) P(doubles) P(no doubles)

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  1. nincompoop
    • one year ago
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    where is your attempt?

  2. anonymous
    • one year ago
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    oh okay so for the or situation would it be like 2/1600 + 2/1600

  3. triciaal
    • one year ago
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    B = blue or brown

  4. anonymous
    • one year ago
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    or B is Brown!!

  5. anonymous
    • one year ago
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    *oh

  6. triciaal
    • one year ago
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    |dw:1436673083490:dw|

  7. triciaal
    • one year ago
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    are we considering only exactly as written in that order 1 red then 2 green or do you need any combination of 1 red and 2 green ?

  8. triciaal
    • one year ago
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    |dw:1436673692973:dw|

  9. triciaal
    • one year ago
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    can you clarify P(doubles) and P(no doubles) how many are you getting?

  10. triciaal
    • one year ago
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    |dw:1436674059198:dw|

  11. triciaal
    • one year ago
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    with replacement means you are putting the chosen bead back in the "pool" before picking again. without replacement means you have one less each time you pull one bead out the group.

  12. triciaal
    • one year ago
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    are you here?

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