At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I meant 2/6 not 2/3
Ok, whenever you add a number to a function like that, you're basically going to shift it up or down by that much. Something called a vertical shift.
So, if you're adding a number 'k' to f(x) to get g(x), count how many vertical spaces they differ by at an x-value. Like, x = 0 would probably be the easiest. How much do the y-values differ at x=0?
Not quite. When x = 0, look at what g(x) is first.
from two to six is four spaces
At x=0, g(x) is 2. Are you following me so far?
So, at x=0, you want to see what f(x) is. What do you think f(x) is when x = 2?
When you're trying to find what the y-value of a function is with a certain x, what you want to do is go to that x-value and go up or down until you get to the line. So, start at x=0 and y=0, and then go up or down until you get to the line, f(x). Does that help?
So if x=2 then f(x)=2 because at x2 the line is at 2/2
Yes. You're right. If you're going to use x=2, then what is g(x) when x = 2?
Yes, g(x) = 6 when x = 2. So now, you want to take the difference of the two numbers, and that'll be what k is :)
so K = 4?
Alright. Thank you very much :))
No problem. Also, in this kind of question, you can use any x-value you want to do it. That's why I said x=0 would be easiest because they y-values are right there on screen, which would've been 2 - (-2) = 4. You get it?