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anonymous
 one year ago
(k+5)x^2  (2k + 3)x + (k + 1) = 0
The roots are real and equal
anonymous
 one year ago
(k+5)x^2  (2k + 3)x + (k + 1) = 0 The roots are real and equal

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campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4real and equal means the discriminant is zero and the discriminant is found using \[\Delta = b^2  4ac\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4you have a = (k + 5) b = (2k + 3) c = (k + 1) so substitute the values then you can solve for k hope it helps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04k^2+9+12k4k^2  20 = 0 ?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4so you have \[[(2k + 3)]^2  4\times (k + 5) \times (k + 1)] = 0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04k^2+9+12k4k^2  20 = 0 ?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4well the 1st part is ok... b^2 = 4k^2 + 12k + 9 4ac = 4(k^2 + 6k + 5) then b^2  4ac : 4k^2 + 12k + 9  4k^2  24k 20 = 0 so collect like terms and solve for k

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04k^2  24k 20????? How???

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4ac: (k + 5)(k + 1) = k^2 + 6k + 5 4ac = 4k^2 + 24k + 20 does that make sense..?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4so in the equation are you happy that a = (k + 5) and c = (k + 1)...?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4so if you multiply a and c (k + 5)(k + 1) = k^2 + 6k + 5 does that make sense..?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4so then 4ac = 4k^2 + 24k + 20 so b^2  4ac is 4k^2 + 12k + 9  4k^2 24k  20 = 0 collect like terms 12k  11 = 0

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4solve for k... 12k = 11 etc

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4well if 12k = 11 k =  11/12 I'd leave it as a fraction.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0 11/12?? It should be +???

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4is that the answer you have been provided..?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have no options.............

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4well are you happy that after collecting like terms 12k  11 = 0 then you can multiply every term by 1 and get 12k + 11 = 0 and then you still get 12k = 11 so k = 11/12
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