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anonymous
 one year ago
49log2*2log7 =?
please do a favour to solve this ques.
anonymous
 one year ago
49log2*2log7 =? please do a favour to solve this ques.

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rajat97
 one year ago
Best ResponseYou've already chosen the best response.0it is in the form xlogy*ylogx

rajat97
 one year ago
Best ResponseYou've already chosen the best response.0what can you do to simplify it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436709166375:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can i do somthing like that

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0I don't think you can do anything with the original one unless using calculator. It is simplest form since (2,7) are relative prime.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.049log2*2log7=7^2log2*2log7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what wud be the next step.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0you are multiplying logarithms (correct?) \(\large\color{black}{ \displaystyle 49\log(2)~\cdot~2\log(7) }\) At first I will ask you, are you sure that it is supposed to be a "•", and not a "+" ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes it is sure http://www.m4maths.com/placementpuzzles.php?SOURCE=amcat&TOPIC=Numerical%20Ability&SUB_TOPIC=Ratio%20and%20Proportion you can check out at this link

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0I don't have a login to this thing, but I of course believe you. I was just asking that for a clarification.....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oke but i wanna ask is there any formula to solve the above equation , which i hve done by drawing. log 2^7^2

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0I think that you can't make it any simpler than \(\large\color{black}{ \displaystyle 49\log(2)~\cdot~2\log(7) =98\log(2)\log(7)}\) (And of course the assumed base is 10, not e)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0Assumed base is also not important tho' for this multiplication, because the assumed base wouldn't matter with this multiplication.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0All we did, is kinda: \(\large\color{black}{ \displaystyle 3a\cdot 4x=12ax }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0we multiplied the coefficients, but you can't really put the logarithms together more than "log(2)log(7)"

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0questions about this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we need to put the values of log 2 and log 7 to calculate the exact answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0as we cannt do anthing with them further

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0If you calculate these values it would be an approximation, and the "exact answer" is what we wrote before 98log(2)log(7)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.049log2*2log7=7^2log2*2log7=7log2^2*2log7=7*2log7=2 this is the solution by somebody on another site . pls see to it

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0No, it is not equivalent to 2. THAT IS WRONG....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i didnt get the logic here

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0no logic... it is wrong... if it had logic it would be much more frightening:O

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have solved it , we have to take 2 as a base in frst case

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0I can't really follow what you did....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have dun blunder to this ques *O*

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0we can't take 2 as the base if it is a log.... you can't rewrite what's in the log, as the base... I mean you can't, but nothing correct is going to get out of it.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0As again, the only thing here that I see valid is: \(\large\color{black}{ \displaystyle 49\log(2)~\cdot~2\log(7) =98\log(2)\log(7)}\)
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