anonymous
  • anonymous
HELP!! Does this make any sense?! http://mhf4u1.pbworks.com/w/page/26838563/Application%20Problem
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
THIS part!!
1 Attachment
anonymous
  • anonymous
i dont understand how they got that :(
Loser66
  • Loser66
What don't you get?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
how did they get b/w 9-13 necklaces ??
Loser66
  • Loser66
the intersections between the graphs|dw:1436711669825:dw|
anonymous
  • anonymous
no but i graphed it and the points were 3 and 19
1 Attachment
Loser66
  • Loser66
|dw:1436711704284:dw|
anonymous
  • anonymous
yes
Loser66
  • Loser66
and between 9 and 13, parabola is higher than the line right?
Loser66
  • Loser66
that is the revenue > the cost, right?
Loser66
  • Loser66
@freckles please help me to finish the explanation. I have to go now.
anonymous
  • anonymous
isnt the parabola higher at 3-19?!
anonymous
  • anonymous
PL HELP!!!
anonymous
  • anonymous
@misssunshinexxoxo
misssunshinexxoxo
  • misssunshinexxoxo
@jim_thompson5910
anonymous
  • anonymous
i think it should be "steph should make 3-19 necklaces each week"
anonymous
  • anonymous
maybe the website is wrong?!??! because it doesnt make sense to me otherwise :(
freckles
  • freckles
\[25n-n^2>55+3.5n \\ 0>n^2+3.5n-25n+55 \\ n^2-21.5n+55<0 \\ 10n^2-215n+550<0 \\ 2n^2-43n+110<0 \\ \text{ this does give } n \in (3,19)\]
freckles
  • freckles
oops \[n \in [3,19]\]
freckles
  • freckles
wanted to but brackets there to show to include the endpoints
freckles
  • freckles
since actually you have the lower endpoint is approximately n=2.97 and the upper endpoint is 18.53 so you could actually say the answer is [3,19) didn't include the 19 because 18.53 is less than 19 but definitely include the 3 since 3 is more than 2.97
freckles
  • freckles
it looks like there was some dyslexia happening there on the website though :p
anonymous
  • anonymous
omg so i was right?! its b/w 3-19 ?
anonymous
  • anonymous
not 13-9?
freckles
  • freckles
yep the weird thing is they even put the right answer after they said the wrong answer
anonymous
  • anonymous
yeah thats what got me confused
anonymous
  • anonymous
thanks a ton though!! :)
freckles
  • freckles
np
anonymous
  • anonymous
@freckles FRECKLES!!! How did you get
anonymous
  • anonymous
n∈[3,19]
anonymous
  • anonymous
??
freckles
  • freckles
well actually n in [3,19) since 19 is a little greater than the actual left endpoint
anonymous
  • anonymous
where did you get the points 3,19? from the graph? or did you get that from the 25n-n^2>55+3.5n??
freckles
  • freckles
\[2n^2-43n+110<0 \\ 2n^2-43n<-110 \\ n^2-\frac{43}{2}n<-55 \\ n^2-\frac{43}{2}n+(\frac{43}{2} \frac{1}{2})^2<-55+(\frac{43}{2} \frac{1}{2})^2 \\ (n-\frac{43}{4})^2<-55+\frac{43^2}{4^2} \\ (n-\frac{43}{4})^2<\frac{-55(16)+43^2}{16} \\ (n-\frac{43}{4})^2<\frac{969}{16} \\ \sqrt{ (n-\frac{43}{4})^2}< \sqrt{\frac{969}{16}} \\ |n-\frac{43}{4}|<\frac{ \sqrt{969}}{4} \\ - \frac{\sqrt{969}}{4}
freckles
  • freckles
I solve the quadratic inequality I had above
anonymous
  • anonymous
so how'd you get 3 and 19 from all that?!
freckles
  • freckles
calculator to approximate both the 43/4-sqrt(969)/4 and 43/4+sqrt(969)/4
anonymous
  • anonymous
sorry im being so difficult, i just really dont understand :(
freckles
  • freckles
\[\frac{\sqrt{969}}{4}+\frac{43}{4} \approx 18.5322 \\ \frac{43}{4}-\frac{\sqrt{969}}{4} \approx 2.96781\]
anonymous
  • anonymous
ohhhhhhh alright
anonymous
  • anonymous
thank you soo so so much omg
freckles
  • freckles
\[2.96781
freckles
  • freckles
or an interval notation [3,19)
freckles
  • freckles
in roster notation {3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18}
freckles
  • freckles
by the way when we say n in [3,19) we should also include where n is a whole number (or you can say integer or whatever )
freckles
  • freckles
lol just trying to be really proper with all the math terminology :p
anonymous
  • anonymous
so is it 3
anonymous
  • anonymous
** \[3\le n \le 19\]
freckles
  • freckles
well I put \[3 \le n < 19\] since 19 isn't actually included
freckles
  • freckles
where n is integer of course

Looking for something else?

Not the answer you are looking for? Search for more explanations.