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anonymous
 one year ago
HELP!! Does this make any sense?!
http://mhf4u1.pbworks.com/w/page/26838563/Application%20Problem
anonymous
 one year ago
HELP!! Does this make any sense?! http://mhf4u1.pbworks.com/w/page/26838563/Application%20Problem

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand how they got that :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did they get b/w 913 necklaces ??

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2the intersections between the graphsdw:1436711669825:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no but i graphed it and the points were 3 and 19

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2and between 9 and 13, parabola is higher than the line right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2that is the revenue > the cost, right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2@freckles please help me to finish the explanation. I have to go now.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0isnt the parabola higher at 319?!

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think it should be "steph should make 319 necklaces each week"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maybe the website is wrong?!??! because it doesnt make sense to me otherwise :(

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[25nn^2>55+3.5n \\ 0>n^2+3.5n25n+55 \\ n^221.5n+55<0 \\ 10n^2215n+550<0 \\ 2n^243n+110<0 \\ \text{ this does give } n \in (3,19)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1oops \[n \in [3,19]\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1wanted to but brackets there to show to include the endpoints

freckles
 one year ago
Best ResponseYou've already chosen the best response.1since actually you have the lower endpoint is approximately n=2.97 and the upper endpoint is 18.53 so you could actually say the answer is [3,19) didn't include the 19 because 18.53 is less than 19 but definitely include the 3 since 3 is more than 2.97

freckles
 one year ago
Best ResponseYou've already chosen the best response.1it looks like there was some dyslexia happening there on the website though :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0omg so i was right?! its b/w 319 ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1yep the weird thing is they even put the right answer after they said the wrong answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah thats what got me confused

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks a ton though!! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@freckles FRECKLES!!! How did you get

freckles
 one year ago
Best ResponseYou've already chosen the best response.1well actually n in [3,19) since 19 is a little greater than the actual left endpoint

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where did you get the points 3,19? from the graph? or did you get that from the 25nn^2>55+3.5n??

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[2n^243n+110<0 \\ 2n^243n<110 \\ n^2\frac{43}{2}n<55 \\ n^2\frac{43}{2}n+(\frac{43}{2} \frac{1}{2})^2<55+(\frac{43}{2} \frac{1}{2})^2 \\ (n\frac{43}{4})^2<55+\frac{43^2}{4^2} \\ (n\frac{43}{4})^2<\frac{55(16)+43^2}{16} \\ (n\frac{43}{4})^2<\frac{969}{16} \\ \sqrt{ (n\frac{43}{4})^2}< \sqrt{\frac{969}{16}} \\ n\frac{43}{4}<\frac{ \sqrt{969}}{4} \\  \frac{\sqrt{969}}{4}<n\frac{43}{4}< \frac{\sqrt{969}}{4} \\ \frac{43}{4}\frac{\sqrt{969}}{4}<n<\frac{\sqrt{969}}{4}+\frac{43}{4} \]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1I solve the quadratic inequality I had above

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so how'd you get 3 and 19 from all that?!

freckles
 one year ago
Best ResponseYou've already chosen the best response.1calculator to approximate both the 43/4sqrt(969)/4 and 43/4+sqrt(969)/4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry im being so difficult, i just really dont understand :(

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{\sqrt{969}}{4}+\frac{43}{4} \approx 18.5322 \\ \frac{43}{4}\frac{\sqrt{969}}{4} \approx 2.96781\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you soo so so much omg

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[2.96781<n<18.5322 \] n can be a whole number only 3 is in that interval but 19 isn't so you can say the inequality is: \[3 \le n <19\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1or an interval notation [3,19)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1in roster notation {3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18}

freckles
 one year ago
Best ResponseYou've already chosen the best response.1by the way when we say n in [3,19) we should also include where n is a whole number (or you can say integer or whatever )

freckles
 one year ago
Best ResponseYou've already chosen the best response.1lol just trying to be really proper with all the math terminology :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0** \[3\le n \le 19\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1well I put \[3 \le n < 19\] since 19 isn't actually included

freckles
 one year ago
Best ResponseYou've already chosen the best response.1where n is integer of course
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