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So the first step is to balance the equation are you able to do that?
I think.... Cu+2AgNO3 --> Cu(NO3)2 +2Ag
Perfect! So now we need to determine which one either the Cu or the AgNO3 is the limiting reagent. Do you happen to know which one it is?
No would it be Cu?
So to determine which one is the limiting reagent we know that the ratio of Cu to Ag is 1:2 and the ratio of AgNO3 to Ag is 1:1 so 4.2 moles of Cu makes 8.4 moles of Ag and we have 6.3 moles of AgNO3 which makes 6.3 moles of Ag so our limiting reagent is actually the AgNO3
Wait how do you know the ratio?
the ratio is found with the stoichometric coefficients so when you balanced it you are finding the ratio
So whats next?
So would NO be worth nothing?? Since the ratio is 1:1 and 6.3 is Ag by itself too? @taramgrant0543664
So the next step since we have our limiting reagent as AgNO3 we will see how much of the Ag is produced Since we have found that AgNO3 and Ag are in the 1:1 ratio 6.3moles of Ag are produced from this reaction
The ratio includes NO as part of the AgNO3 compound this reaction is a single displacement reaction so the NO3 transfers to the Cu leaving the Ag by itself
Do you have everything so far?
so i would subtract 6.3 from 8.4?
Not exactly so we know that 6.3 moles of Ag are produced in this reaction and the ratio of Cu to Ag is 1:2 so we have to divide the 6.3 by two getting 3.15 and then we can subtract the 4.2-3.15= the amount left over
The reason why we don't use the 8.4 moles because that is us saying how much could be made from the Cu but we used the AgNO3 as our limiting agent
@taramgrant0543664 So it would be 1.05grams/mol of Cu?
It would be 1.05 moles of Cu not the 1.05g/mol
oh ok thx