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anonymous

  • one year ago

If 4.2 moles of copper metal reacts with 6.3 moles of silver nitrate, how many moles of silver metal can be formed, and how many moles of the excess reactant will be left over when the reaction is complete? Unbalanced equation: Cu + AgNO3 → Cu(NO3)2 + Ag Be sure to show all of your work. @taramgrant0543664 @photon336

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  1. taramgrant0543664
    • one year ago
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    So the first step is to balance the equation are you able to do that?

  2. anonymous
    • one year ago
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    I think.... Cu+2AgNO3 --> Cu(NO3)2 +2Ag

  3. taramgrant0543664
    • one year ago
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    Perfect! So now we need to determine which one either the Cu or the AgNO3 is the limiting reagent. Do you happen to know which one it is?

  4. anonymous
    • one year ago
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    No would it be Cu?

  5. taramgrant0543664
    • one year ago
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    So to determine which one is the limiting reagent we know that the ratio of Cu to Ag is 1:2 and the ratio of AgNO3 to Ag is 1:1 so 4.2 moles of Cu makes 8.4 moles of Ag and we have 6.3 moles of AgNO3 which makes 6.3 moles of Ag so our limiting reagent is actually the AgNO3

  6. anonymous
    • one year ago
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    Wait how do you know the ratio?

  7. taramgrant0543664
    • one year ago
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    the ratio is found with the stoichometric coefficients so when you balanced it you are finding the ratio

  8. anonymous
    • one year ago
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    So whats next?

  9. anonymous
    • one year ago
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    So would NO be worth nothing?? Since the ratio is 1:1 and 6.3 is Ag by itself too? @taramgrant0543664

  10. taramgrant0543664
    • one year ago
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    So the next step since we have our limiting reagent as AgNO3 we will see how much of the Ag is produced Since we have found that AgNO3 and Ag are in the 1:1 ratio 6.3moles of Ag are produced from this reaction

  11. taramgrant0543664
    • one year ago
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    The ratio includes NO as part of the AgNO3 compound this reaction is a single displacement reaction so the NO3 transfers to the Cu leaving the Ag by itself

  12. taramgrant0543664
    • one year ago
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    Do you have everything so far?

  13. anonymous
    • one year ago
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    so i would subtract 6.3 from 8.4?

  14. taramgrant0543664
    • one year ago
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    Not exactly so we know that 6.3 moles of Ag are produced in this reaction and the ratio of Cu to Ag is 1:2 so we have to divide the 6.3 by two getting 3.15 and then we can subtract the 4.2-3.15= the amount left over

  15. taramgrant0543664
    • one year ago
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    The reason why we don't use the 8.4 moles because that is us saying how much could be made from the Cu but we used the AgNO3 as our limiting agent

  16. anonymous
    • one year ago
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    @taramgrant0543664 So it would be 1.05grams/mol of Cu?

  17. taramgrant0543664
    • one year ago
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    It would be 1.05 moles of Cu not the 1.05g/mol

  18. anonymous
    • one year ago
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    oh ok thx

  19. taramgrant0543664
    • one year ago
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    No problem!

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