Falling_In_Katt
  • Falling_In_Katt
***WILL MEDAL*** divide. \[\frac{ 8y ^{2}-4y+1 }{ 2y-1 }\]
Mathematics
schrodinger
  • schrodinger
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Mehek14
  • Mehek14
divide 8/2 and subtract the exponents \[y ^{2-1}\]
Mehek14
  • Mehek14
alekos
  • alekos
I would have thought that long division was in order

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Falling_In_Katt
  • Falling_In_Katt
4y^1?
Mehek14
  • Mehek14
you can just put \(4y\)
Mehek14
  • Mehek14
now -4/2
Falling_In_Katt
  • Falling_In_Katt
-2
Mehek14
  • Mehek14
and \(\dfrac{y}{y}\)
Mehek14
  • Mehek14
\(y^{1-1}\)
Falling_In_Katt
  • Falling_In_Katt
y^0
Mehek14
  • Mehek14
so y cancels out \(4y-2\)
Mehek14
  • Mehek14
last step \(\dfrac{-1}{1}\)
Mehek14
  • Mehek14
actually the other way \(\dfrac{1}{-1}\) doesn't really matter
Falling_In_Katt
  • Falling_In_Katt
-1
Mehek14
  • Mehek14
so your answer is \(4y-2-1\)
Falling_In_Katt
  • Falling_In_Katt
oh okay. thank you!
Mehek14
  • Mehek14
combine -2 - 1 \(4y-3\)
Mehek14
  • Mehek14
and yw
alekos
  • alekos
No way. That's not right
alekos
  • alekos
The correct answer using polynomial long division is 4y + 1/(2y-1)

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