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Falling_In_Katt

  • one year ago

***WILL MEDAL*** divide. \[\frac{ 8y ^{2}-4y+1 }{ 2y-1 }\]

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  1. Mehek14
    • one year ago
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    divide 8/2 and subtract the exponents \[y ^{2-1}\]

  2. Mehek14
    • one year ago
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    @Falling_In_Katt ?

  3. alekos
    • one year ago
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    I would have thought that long division was in order

  4. Falling_In_Katt
    • one year ago
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    4y^1?

  5. Mehek14
    • one year ago
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    you can just put \(4y\)

  6. Mehek14
    • one year ago
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    now -4/2

  7. Falling_In_Katt
    • one year ago
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    -2

  8. Mehek14
    • one year ago
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    and \(\dfrac{y}{y}\)

  9. Mehek14
    • one year ago
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    \(y^{1-1}\)

  10. Falling_In_Katt
    • one year ago
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    y^0

  11. Mehek14
    • one year ago
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    so y cancels out \(4y-2\)

  12. Mehek14
    • one year ago
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    last step \(\dfrac{-1}{1}\)

  13. Mehek14
    • one year ago
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    actually the other way \(\dfrac{1}{-1}\) doesn't really matter

  14. Falling_In_Katt
    • one year ago
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    -1

  15. Mehek14
    • one year ago
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    so your answer is \(4y-2-1\)

  16. Falling_In_Katt
    • one year ago
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    oh okay. thank you!

  17. Mehek14
    • one year ago
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    combine -2 - 1 \(4y-3\)

  18. Mehek14
    • one year ago
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    and yw

  19. alekos
    • one year ago
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    No way. That's not right

  20. alekos
    • one year ago
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    The correct answer using polynomial long division is 4y + 1/(2y-1)

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