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vera_ewing
 one year ago
The temperature of a chemical reaction ranges between 30°C and 70°C. The temperature is at its lowest point when t = 0 and completes one cycle over a sixhour period. What is a sine function that would model this reaction?
vera_ewing
 one year ago
The temperature of a chemical reaction ranges between 30°C and 70°C. The temperature is at its lowest point when t = 0 and completes one cycle over a sixhour period. What is a sine function that would model this reaction?

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vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino f(t) = 50 sin 10t + 20 ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the amplitude of your function, is: \[\Large A = \frac{{\max value  \min value}}{2} = \frac{{70  30}}{2} = ...?\]

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0f(t) = 20 sin 10t + 50 is the answer?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we can write: \[\Large f\left( t \right) = 20\sin \left( {Bt} \right) + 50\] since we have these limit values: \[\Large 30 \leqslant 20\sin \left( {Bt} \right) + 50 \leqslant 70\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now we have to determine the value of the constant B

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0So it's f(t) = 20 sin pi/5 t + 50 ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I think that we have: \[\Large B = \frac{{2\pi }}{6}\] since our function has to assume the same values after 6 hours

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1therefore: \[\Large f\left( t \right) = 20\sin \left( {\frac{{2\pi }}{6}t} \right) + 50\] is the right function

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Those are my answer choices ^

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1please wait a moment, I'm pondering...

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1please look at this drawing:

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1maybe there is a typo since we can rewrite our function as below: \[\Large f\left( t \right) = 20\sin \left( {\frac{\pi }{3}t} \right) + 50\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1please wait a moment, I understand

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I confirm my answer above

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0So which one should I choose?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1try with the last option, please

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1is the period T=10 hours?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I think that there is a typo, namely: T=10 hours and not T=6 hours
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