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anonymous

  • one year ago

How many solutions does the system of equations have? 3x=-12y+15 and x+4y=5

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  1. anonymous
    • one year ago
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    If the equations contradict each other, then you have no solutions. If the equations are equivalent to each other, you have infinite solutions. If the equations are distinct, you will get precisely one solution.

  2. anonymous
    • one year ago
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    You may start off by rearranging the first equation so that the x and y variables match up.

  3. anonymous
    • one year ago
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    \[3x+12y=15\]

  4. anonymous
    • one year ago
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    \[x+4y=5\]

  5. anonymous
    • one year ago
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    Notice however, that if you multiply the second equation by a factor of 3, you get the same equation as the first equation.

  6. anonymous
    • one year ago
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    Since they are equivalent to each other, you will have infinite solutions.

  7. anonymous
    • one year ago
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    thank you, can you help me with the answer to more?

  8. anonymous
    • one year ago
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    Sure, please feel free to award a medal if you believe the above response was helpful.

  9. anonymous
    • one year ago
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    yeah, you really were! don't need any more help though actually. thank you though!!

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