A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

If sin theta=3/5 and theta is in quad 2 the exact form of csc (pi/2-theta) is...? Just want to make sure if this works??

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sinθ = 3/5 csc(π/2 - θ) = secθ = 1/cosθ = -4/5

  2. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1436736243879:dw|

  3. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    given sin = 3/5 and in quad 2

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @triciaal So what does that mean?

  5. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    csc = 1/sin = hypotenuse / opposite 5/-4

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The answer is -5/4 then?

  7. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1436737161908:dw|

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What do I do with that?

  9. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    your question "the exact form of csc (pi/2-theta) is?"

  10. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    shouldn't it be between -1 and 1 only?

  11. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    "sinθ = 3/5 csc(π/2 - θ) = secθ = 1/cosθ = -4/5" in your work here the only mistake you made was not flipping -4/5 that cos(theta)=-4/5 so 1/cos(theta) is the reciprocal of that

  12. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    csc = hypotenuse/ opposite

  13. ybarrap
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1436737547332:dw| However, since we are in the 2nd quadrant $$ -\csc\left (\frac{\pi}{2}-\theta\right )=\frac{{\bf\color{red}{-}}5}{~~4} $$ Note the negative corresponding to the value of \(x\) in the 2nd quadrant.

  14. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @zepdrix why/when is the value < -1 in general?

  15. zepdrix
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Trish :) Maybe you're thinking about sine and cosine, which have restricted output values between 1 and -1

  16. zepdrix
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That's the only way they will satisfy a triangle `hypotenuse longer than other sides`\[\large\rm \sin \theta=\frac{opposite}{hypotenuse}=\frac{shorter}{longer}\lt1\]But for Cosecant, I guess we have the reverse going on, ya? We always need to be 1 or larger.\[\Large\rm \csc \theta=\frac{hypotenuse}{opposite}=\frac{longer}{shorter}\gt1\]

  17. ybarrap
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Does this make sense? |dw:1436738761632:dw|

  18. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @zepdrix thanks just never thought about it @ybarrap thanks for the CAST diagram but I was checking the limit ; not if positive or negative

  19. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @ybarrap no tan on your chart

  20. ybarrap
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1436739672137:dw|

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Sorry guys I'm back! So i think I got the answer this time around! @triciaal @zepdrix

  22. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -1/3/5 I think @zepdrix @triciaal @freckles

  23. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    what is that the answer to?

  24. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    are you looking at a new question?

  25. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No for the one I put on

  26. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh I guess you didn't understand what anyone posted :p

  27. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yeah nothing at all XD

  28. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    This is the only question I can't get!! :////

  29. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok let's start from the beginning this shouldn't be long at all

  30. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    "sinθ = 3/5 csc(π/2 - θ) = secθ = 1/cosθ = -4/5" do you remember this is what you first posted here?

  31. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    this was your first try here anyways

  32. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yeah thats what I did, but I figured it was wrong

  33. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it is a little wrong

  34. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the first part is totally awesome

  35. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the second part the part where you say 1/cos(theta)=-4/5 is a little off

  36. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes cos(theta)=-4/5 but what is 1/cos(theta)=?

  37. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if I tell you a=2/5 then what is 1/a=?

  38. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    or how about this if I tell you 1/a=5/2 then a=?

  39. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    a and 1/a are reciprocals of one another that means they are the "flippings of each other" like 2 and 1/2 are reciprocals and 2/5 and 5/2 are reciprocals and -2/5 and -5/2 are reciprocals

  40. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so if I say a=2/5 then 1/a=5/2 or if I say 1/a=5/2 then a=2/5

  41. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so if cos(theta)=-4/5 then 1/cos(theta)=?

  42. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if you want to replace cos(theta) with a you can if a=-4/5 then 1/a=?

  43. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @freckles Alright I think I need a little bit to take this all in cuz you just shot me a whole bunch of stuff at me XD I think I get what your saying let me see what I can do

  44. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    take your time

  45. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Wait so would it be -5/4 then??? *fingers crossed right now that its right** haha

  46. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes yes !!!

  47. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    YYAYYY!!

  48. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    -5/4 is indeed the reciprocal of -4/5

  49. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So where do you go on from there? Is there more to be done??

  50. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    nope

  51. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ohmygod that simple for a question like this? My mind is just blown right now .... XD

  52. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \["\sinθ = 3/5 \\ \csc(π/2 - θ) = \secθ = 1/\cosθ = -4/5" \\ \text{ so the correcting your work would look like this: } \\ \csc(\frac{\pi}{2}-\theta)=\sec(\theta)=\frac{1}{\cos(\theta)}=\frac{1}{\frac{-4}{5}}=\frac{-5}{4}\]

  53. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    by the way you know that first thing you used it called a cofunction identity most people forget that one so you are doing awesome!

  54. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @freckles Thanks again seriously!! Haha really helped! Literally am beating myself up not knowing lol

  55. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i think we were all working on our algebra in trig and even in calculus

  56. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    algebra/arithemetic

  57. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    and/or

  58. freckles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    guess what you are going to have to know so much algebra for calculus you are going to think you never learned algebra :p well that has been my experience with some anyways I'm kind a kidding. I know you are going do okay especially since you can always get help if you need it.

  59. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Haha true!! thanks again! I know with Calc I am going to need lots of help especially!!

  60. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    math is fun just takes lots of practice

  61. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.