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Treat them as if you were completing the square

Try it for the rest then you can compare their lines of symmetry

I see!

so for the 2nd one, take out the the negative. -x^2+2=-(x^2-2), line of symmetry is x=2

Yep! I understand now. Thank you so much!

so factorising 2 out \[2x^2-4x+3=2(x^2-2x)+3=2(x-1)^2-1+3\] line of symmetry should be positive 1

its still gonna be +3 in the brackets so thats a -3 translation, did you type up f(x) wrong?

A. f, g, h

B. h, g, f
C. g, h, f
D. h, f, g

so it should be in the order (small to greatest), f(x), h(x), g(x) :/

But our findings would suggest f, h, g, like you said, but it's not an option.

It must be an error in the module.

oh sorry i made a mistake with g

thus the order would be f, g, h?

yes

it was my fault i thought -(x^2-2) was -(x-2)^2 XD