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YumYum247
 one year ago
yelp!!!
YumYum247
 one year ago
yelp!!!

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YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1This is how i attempted to do the question..... Fn = nF1 (16.5Hz) Fn = 16.5Hz The fundamental frequency is 16.5Hz

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1can someone please give me a hint on how to solve for the speed of the wave...V = d/t How do i find time here?????????????? :(

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436754247641:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[v = \lambda f\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0What did you get for the first answer?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1the fundamental frequency/natural frequency of the string is 16.5Hz

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0But it's asking for the string

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge f_{freq} = 3 f_{string}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Where your \[f_{freq} = 16.5 Hz\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1fundamental frequency is the lowest frequency that a system can produce to make a standing wave.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1that would the natural frequency in the 3rd harmonic phase.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1i did a question earlier related tho this, and the fundamental frequency of the wave was the very lowest that a wave produced in a fixed postion....like this dw:1436755214463:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1that is the fundamental frequency of the wave....F = 30/.20 = 150Hz So the other two frequencies i had to figure out that make the standing waves were.... Fn = nF2 Fn = F2(150) = 300Hz Fn = nF3 Fn = F3(150) = 450Hz

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436755541130:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436755603442:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436755633977:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1but how do i find the time of wavelength?????????????:/

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3*can someone please give me a hint on how to solve for the speed of the wave* its a standing wave and its wave form is not actually visibly *travelling* but it still has "velocity" \( v = \frac{2 \ L \ f_n}{n} \) so velocity \(v\) and freq \(f_3\) for the 3rd harmonic are related as follows: \( v = \frac{2 \ L \ f_3}{3} \) or \( f_3 = \frac{3v}{2L} \)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Thank you Irishman!!! :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1and is my fundamental frequency correct?????????????????? @IrishBoy123

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3this is a long old thread so let me step through it as i see it and you judge if this makes sense to you: first there is resonance with the 16.5Hz source so we can say: dw:1436805378856:dw v is fixed, it is a consequence if the tension in and density of the string. so the "fundamental harmonic will look like this: dw:1436805640680:dw if this makes sense, we can do the last bit and look again at that equation i posted as i think it is important to note that it is totally derivable and not something of a lack box. this fits nicely with part (iii) of the question so i hope this is all going according to plan.....

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3forgive "lack box" [= "black box"] and myriad other typos....

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3in terms of what can be a resonant frequency, here is the beginning of the possible standing wave patterns: dw:1436806502148:dw IOW: \(\lambda_n = \frac{2 L}{n}\) and \(v = f . \lambda\) which gives us the formula i quoted previously, \(f_n = \frac{v}{\lambda} = \frac{n . v}{2L}\) ergo, resonant frequencies go in integer multiples of \(\frac{ v}{2L}\) which here is \(\frac{66}{2*6} = 5.5Hz\). and \(\frac{28.5}{5.5} = ???\) does that make sense to you? do you agree?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436844986642:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436845232173:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1f1 = 5.5Hz and V = 66m/sec

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1The next question asks me to find whether or not the new frequency of 28.5Hz would make a standing wave on the spring??????And this is how i did it.......dw:1436847792123:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436847968394:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1i think in order for the new frequency to produce a complete standing wave, it has to be twice as big as the fundamental frequency....in this case 33Hz to make the next standing wave on the string......am i right???????Oo

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1@IrishBoy123 @Astrophysics the question asks me to find the minimum length of air in a column required for resonate??????This is how i did it...please check my work :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436850740578:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436851048790:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1is that the minimum length of air/ fundamental length of air????????

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1@Michele_Laino Can you please check my work??????

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1the question asks me to find the fundamental frequency....i've done it up there but no one bothered to check my work, could you please give me a hand here???

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0I'm very sorry, I don't know your answer, since in my physics courses I have not studied acoustics

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Elsa213 I'm not good at physics...sorry :/

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1aight so this is my fundamental frequency.dw:1436887286398:dw