yelp!!!

- YumYum247

yelp!!!

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- schrodinger

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- YumYum247

##### 1 Attachment

- YumYum247

This is how i attempted to do the question.....
Fn = nF1 (16.5Hz)
Fn = 16.5Hz
The fundamental frequency is 16.5Hz

- YumYum247

can someone please give me a hint on how to solve for the speed of the wave...V = d/t
How do i find time here?????????????? :(

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## More answers

- YumYum247

|dw:1436754247641:dw|

- Astrophysics

\[v = \lambda f\]

- Astrophysics

What did you get for the first answer?

- YumYum247

the fundamental frequency/natural frequency of the string is 16.5Hz

- Astrophysics

But it's asking for the string

- Astrophysics

\[\huge f_{freq} = 3 f_{string}\]

- Astrophysics

Where your \[f_{freq} = 16.5 Hz\]

- YumYum247

fundamental frequency is the lowest frequency that a system can produce to make a standing wave.

- YumYum247

that would the natural frequency in the 3rd harmonic phase.

- YumYum247

i did a question earlier related tho this, and the fundamental frequency of the wave was the very lowest that a wave produced in a fixed postion....like this |dw:1436755214463:dw|

- YumYum247

that is the fundamental frequency of the wave....F = 30/.20 = 150Hz
So the other two frequencies i had to figure out that make the standing waves were....
Fn = nF2
Fn = F2(150) = 300Hz
Fn = nF3
Fn = F3(150) = 450Hz

- YumYum247

|dw:1436755541130:dw|

- YumYum247

|dw:1436755603442:dw|

- YumYum247

|dw:1436755633977:dw|

- YumYum247

but how do i find the time of wavelength?????????????:/

- YumYum247

@mathmate

- YumYum247

@pooja195

- IrishBoy123

*can someone please give me a hint on how to solve for the speed of the wave*
its a standing wave and its wave form is not actually visibly *travelling* but it still has "velocity" \( v = \frac{2 \ L \ f_n}{n} \)
so velocity \(v\) and freq \(f_3\) for the 3rd harmonic are related as follows: \( v = \frac{2 \ L \ f_3}{3} \) or \( f_3 = \frac{3v}{2L} \)

- YumYum247

Thank you Irishman!!! :)

- YumYum247

and is my fundamental frequency correct?????????????????? @IrishBoy123

- IrishBoy123

this is a long old thread so let me step through it as i see it and you judge if this makes sense to you:
first there is resonance with the 16.5Hz source so we can say:
|dw:1436805378856:dw|
v is fixed, it is a consequence if the tension in and density of the string. so the "fundamental harmonic will look like this:
|dw:1436805640680:dw|
if this makes sense, we can do the last bit and look again at that equation i posted as i think it is important to note that it is totally derivable and not something of a lack box. this fits nicely with part (iii) of the question so i hope this is all going according to plan.....

- IrishBoy123

forgive "lack box" [= "black box"] and myriad other typos....

- IrishBoy123

in terms of what can be a resonant frequency, here is the beginning of the possible standing wave patterns:
|dw:1436806502148:dw|
IOW: \(\lambda_n = \frac{2 L}{n}\) and \(v = f . \lambda\) which gives us the formula i quoted previously, \(f_n = \frac{v}{\lambda} = \frac{n . v}{2L}\)
ergo, resonant frequencies go in integer multiples of \(\frac{ v}{2L}\) which here is \(\frac{66}{2*6} = 5.5Hz\).
and \(\frac{28.5}{5.5} = ???\)
does that make sense to you? do you agree?

- YumYum247

|dw:1436844986642:dw|

- YumYum247

|dw:1436845232173:dw|

- YumYum247

f1 = 5.5Hz
and V = 66m/sec

- YumYum247

The next question asks me to find whether or not the new frequency of 28.5Hz would make a standing wave on the spring??????And this is how i did it.......|dw:1436847792123:dw|

- YumYum247

|dw:1436847968394:dw|

- YumYum247

i think in order for the new frequency to produce a complete standing wave, it has to be twice as big as the fundamental frequency....in this case 33Hz to make the next standing wave on the string......am i right???????O-o

- YumYum247

@IrishBoy123 @Astrophysics the question asks me to find the minimum length of air in a column required for resonate??????This is how i did it...please check my work :)

##### 1 Attachment

- YumYum247

|dw:1436850740578:dw|

- YumYum247

|dw:1436851048790:dw|

- YumYum247

is that the minimum length of air/ fundamental length of air????????

- YumYum247

@Michele_Laino Can you please check my work??????

- YumYum247

the question asks me to find the fundamental frequency....i've done it up there but no one bothered to check my work, could you please give me a hand here???

- Michele_Laino

I'm very sorry, I don't know your answer, since in my physics courses I have not studied acoustics

- YumYum247

Aawwnnnn!!! :(

- YumYum247

@Elsa213

- Elsa213

@dan815

- Elsa213

@sleepyhead314

- Elsa213

@teagirl7630

- anonymous

@Elsa213 I'm not good at physics...sorry :/

- YumYum247

aight so this is my fundamental frequency.|dw:1436887286398:dw|