A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

1st ODE !

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[x'=(x-t)^2+1\]

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    This thing isn't liniar any ideas ?

  3. zepdrix
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Hmm I have an idea.. but it's not giving me the same solution as Wolfram.. So I'm thinking I made a boo boo somewhere. I'll at least show you my attempt

  4. zepdrix
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Let \(\large\rm u=x-t\) Differentiating our sub with respect to time gives \(\large\rm u'=x'-1\qquad\to\qquad x'=u'+1\) Subbing everything in gives us,\[\large\rm u'+1=(u)^2+1\]\[\large\rm u'=u^2\]And then just seperation, ya? :o

  5. zepdrix
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Ooo goodie! I actually am getting the same as wolfram, i just didn't simplify it far enough :)

  6. zepdrix
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Able to make sense of that? It should be correct :O

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thx

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1436763190196:dw| Am I right @zepdrix ?

  9. zepdrix
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    A little hard to read that last line. Lemme just make a note that you should be careful to include your constant of integration at this step.\[\large\rm -\frac{1}{u}=t+c\]Put the negative on the other side,\[\large\rm \frac{1}{u}=c-t\]Solving for u,\[\large\rm \frac{1}{c-t}=u\]Then you need to undo your substitution. Remember, we're trying to solve for x(t).

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    aha thx again

  11. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.