## Nick88888888 one year ago find the domain function of f(x) =

1. Nick88888888

|dw:1436769998922:dw|

2. anonymous

IS this whole thing equal to y?

3. Nick88888888

what do you mean .-.?

4. anonymous

The domain is restricted by the radicand

5. anonymous

x+3>0

6. anonymous

x>-3 Domain has to be [-3,oo)

7. Astrophysics

$x \ge - 3$

8. Astrophysics

$[ { x \in \mathbb{R} : x \ge -3 } ]$ should be squiggly brackets but oh well

9. Nick88888888

@Deeezzzz @Astrophysics ok so it gives me 4 options which is x â¥ 0 , All Real Numbers , x â¥ 1 , x > 0

10. Nick88888888

and ive looked at how to do this on other sites and it kept giving me ∈R stuff :/

11. Astrophysics

That is called set builder notation, you should really learn it, will not take you long http://www.mathsisfun.com/sets/set-builder-notation.html

12. Astrophysics

Your options aren't useful as it's giving symbols, just take image of your question and post it

13. Nick88888888

@Astrophysics

14. Astrophysics

I'm not sure what those symbols mean, and those answers do not make sense to me, maybe someone else can explain the significance of those symbols? @ganeshie8 perhaps

15. Astrophysics

Ah zz is here, maybe he can help

16. zzr0ck3r

$$\sqrt[3]{-1}=-1$$

17. zzr0ck3r

i.e. there are no domain restrictions

18. zzr0ck3r

Does this make sense?

19. Astrophysics

I think you maybe thinking of $(x+3)^3-1$

20. ganeshie8

$\large f(x) = \sqrt[3]{~x~}$ the usual definition is for all real numbers

21. Astrophysics

That was my initial thought, until I wolframmed it xD

22. Astrophysics

But in any case, what are the other symbols?

23. ganeshie8

definitely not math, they look chinese to me

24. Nick88888888

Lol

25. zzr0ck3r

I am not thinking about x^3, I am thinking of the cube root. $$\sqrt[a]{x}$$ has domain all real numbers for all a odd, if a is even then it cant be negative

26. Astrophysics

Oh ok, I thought it was some other way for interval notation

27. zzr0ck3r

It is just him coping from something that is not latex...

28. Astrophysics

Haha, alright thanks zz and ganeshie

29. zzr0ck3r

I am guessing one should say $$x\ge 1$$