- Nick88888888

find the domain function of f(x) =

- chestercat

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- Nick88888888

|dw:1436769998922:dw|

- anonymous

IS this whole thing equal to y?

- Nick88888888

what do you mean .-.?

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## More answers

- anonymous

The domain is restricted by the radicand

- anonymous

x+3>0

- anonymous

x>-3
Domain has to be [-3,oo)

- Astrophysics

\[x \ge - 3\]

- Astrophysics

\[[ { x \in \mathbb{R} : x \ge -3 } ]\] should be squiggly brackets but oh well

- Nick88888888

@Deeezzzz @Astrophysics ok so it gives me 4 options which is x â¥ 0
, All Real Numbers ,
x â¥ 1 ,
x > 0

- Nick88888888

and ive looked at how to do this on other sites and it kept giving me ∈R stuff :/

- Astrophysics

That is called set builder notation, you should really learn it, will not take you long http://www.mathsisfun.com/sets/set-builder-notation.html

- Astrophysics

Your options aren't useful as it's giving symbols, just take image of your question and post it

- Nick88888888

##### 1 Attachment

- Astrophysics

I'm not sure what those symbols mean, and those answers do not make sense to me, maybe someone else can explain the significance of those symbols? @ganeshie8 perhaps

- Astrophysics

Ah zz is here, maybe he can help

- zzr0ck3r

\(\sqrt[3]{-1}=-1\)

- zzr0ck3r

i.e. there are no domain restrictions

- zzr0ck3r

Does this make sense?

- Astrophysics

I think you maybe thinking of \[(x+3)^3-1\]

- ganeshie8

\[\large f(x) = \sqrt[3]{~x~}\]
the usual definition is for all real numbers

- Astrophysics

That was my initial thought, until I wolframmed it xD

- Astrophysics

But in any case, what are the other symbols?

- ganeshie8

definitely not math, they look chinese to me

- Nick88888888

Lol

- zzr0ck3r

I am not thinking about x^3, I am thinking of the cube root. \(\sqrt[a]{x}\) has domain all real numbers for all a odd, if a is even then it cant be negative

- Astrophysics

Oh ok, I thought it was some other way for interval notation

- zzr0ck3r

It is just him coping from something that is not latex...

- Astrophysics

Haha, alright thanks zz and ganeshie

- zzr0ck3r

I am guessing one should say \(x\ge 1\)

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