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Nick88888888

  • one year ago

Findthe domain and the range of the following function: y = √ 12x + 24?

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  1. Nick88888888
    • one year ago
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    |dw:1436775868610:dw|

  2. Astrophysics
    • one year ago
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    \[12x+24 \ge 0\] solve for x for the domain, the range is all the y values, so that should be somewhat obvious \[f \in \mathbb{R}: f \ge 0\]

  3. Astrophysics
    • one year ago
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    |dw:1436776239610:dw| notice the graph agrees

  4. Nick88888888
    • one year ago
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    wait so what did you do with the square root?

  5. Astrophysics
    • one year ago
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    Well, square root only takes positive numbers, so we set it up as such.

  6. Astrophysics
    • one year ago
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    That's the only time it's defined

  7. Nick88888888
    • one year ago
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    would this be 1 way to do it? y = SqrRoot (12x + 25) 12x+24>=0 giving a domain Real values >= -2. The range of y is y>=0.

  8. Astrophysics
    • one year ago
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    y is all real numbers that are y > = 0

  9. Astrophysics
    • one year ago
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    The range*

  10. Astrophysics
    • one year ago
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    I don't know how your teacher wants the answers, so I can't say.

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