• anonymous
4. A poster of height 36 in. is mounted on a wall so that its lower edge is 12 in. above the eye level of an observer. How far from the wall should the observer stand so that the viewing angle  subtended at his eye by the poster is as large as possible?
MIT 18.01 Single Variable Calculus (OCW)
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • katieb
I got my questions answered at in under 10 minutes. Go to now for free help!
  • anonymous
answer is 24. let two angles k1 and k2 such that tan(k1) is 12 divided by x where x is the distance to be found. and tan( k1 + K2) is 48 divided by x. make quadratic in x where u will get 1296- 2304tank2 in underroot. now tan k2 comes to be 0.75 . soving further x is 24.

Looking for something else?

Not the answer you are looking for? Search for more explanations.