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anonymous
 one year ago
This is the parametric plot from
Clear[x, y, z, r, t, f,surface, threedims];
{x[r_, t_], y[r_, t_], z[r_, t_]} = {1, 0, 1} + {r Cos[t], r Sin[t], 0};
x[r,t]
y[r,t]
z[r,t]
surface = ParametricPlot3D[{x[r, t], y[r, t], z[r, t]}, {r, 0, 2}, {t, 0, 2 Pi}];
threedims = Axes3D[3];
Show[threedims, surface, ViewPoint > CMView, PlotRange > All, Boxed > False]
https://drive.google.com/file/d/0BXUShsowTMUd0X3pybjJaVEU/view?usp=sharing
anonymous
 one year ago
This is the parametric plot from Clear[x, y, z, r, t, f,surface, threedims]; {x[r_, t_], y[r_, t_], z[r_, t_]} = {1, 0, 1} + {r Cos[t], r Sin[t], 0}; x[r,t] y[r,t] z[r,t] surface = ParametricPlot3D[{x[r, t], y[r, t], z[r, t]}, {r, 0, 2}, {t, 0, 2 Pi}]; threedims = Axes3D[3]; Show[threedims, surface, ViewPoint > CMView, PlotRange > All, Boxed > False] https://drive.google.com/file/d/0BXUShsowTMUd0X3pybjJaVEU/view?usp=sharing

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would this be considered a curve or a surface, and why?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the images are the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was thinking this would be considered a surface, but I'm not sure how or why I can assert this as a fact.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, the picture came out blank?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think maybe the rule is that a curve is a 1 dimensional object in a 2d or 3d space.. I know the circle is 1 dimensional.. And a surface is a 2d object in a 3d space. But I am not sure if a circle within a circle is considered a surface, or if it is just two curves.. or multiple curves.. My guess is that as soon as you add the 2nd circle, it becomes a 2d object.. so being in a 3d space, this becomes a surface.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @freckles @ikram002p @SithsAndGiggles @Zarkon . Please.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Considering this is a function of two parameters, I think it qualifies as a surface. Compare to a function like `{x[t_] = Cos[t], y[t_] = Sin[t], z[t_] = t}`, which generates a helix, which is more like a curve or contour.
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