anonymous
  • anonymous
Find the exact area of the region bounded by two concentric circles with radii 10 inches and 6 inches. a) 16pi b) 64pi c) 88pi
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@satellite73
anonymous
  • anonymous
@TheSmartOne
anonymous
  • anonymous
big area minus small earea

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More answers

anonymous
  • anonymous
\[\pi r^2\] big area is \[100\pi\]
anonymous
  • anonymous
small area ?
anonymous
  • anonymous
big area minus small area =211 right/
anonymous
  • anonymous
?
anonymous
  • anonymous
i think you are missing that there has to be a \(pi\) in the answer
anonymous
  • anonymous
Wait what?
anonymous
  • anonymous
Oh
anonymous
  • anonymous
\[100\pi-36\pi=?\]
anonymous
  • anonymous
87pi
anonymous
  • anonymous
So the answer is C?
anonymous
  • anonymous
your arithmetic is worse than mine even !!
anonymous
  • anonymous
Really/
anonymous
  • anonymous
\[100-36=?\]
anonymous
  • anonymous
Oh it's 77
anonymous
  • anonymous
lolol
anonymous
  • anonymous
you need a calculator
anonymous
  • anonymous
Sorry. I know it's like 10:30 in the morning, but it takes me awhile to wake up
anonymous
  • anonymous
yeah here too
anonymous
  • anonymous
Really?
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=100-36
anonymous
  • anonymous
let me know when you get \(64\pi\) ...
anonymous
  • anonymous
is this clear or no? (no is a fine answer, just asking)
anonymous
  • anonymous
Omg I do need a calculator
anonymous
  • anonymous
Ima go get one real quick off google
anonymous
  • anonymous
I used to be good at this
anonymous
  • anonymous
use the link i sent wolfram alpha is great
anonymous
  • anonymous
not that you need a calculator to subtract \(100-36\) but still
anonymous
  • anonymous
Oh okay nevermind then. I done already looked at it
anonymous
  • anonymous
yeash
anonymous
  • anonymous
I just realized that 100-30=70 and 100-36=64 cus 10-6=4
anonymous
  • anonymous
however you like to think about it, yes
anonymous
  • anonymous
Oh and can you help this one kid with his algebra? He's new to the site and he looks like he needs help
anonymous
  • anonymous
sure why not?
anonymous
  • anonymous
who is it?
anonymous
  • anonymous
The same kid you tried to help before. He still doesn't understand what you told him and now he's calling to me for help and I don't necessarily remember how to do this stuff
anonymous
  • anonymous
@satellite73

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