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anonymous

  • one year ago

What is the sum of a 7-term geometric series if the first term is 6, the last term is 24,576, and the common ratio is -4? -32,766 -19,662 19,662 32,766

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  1. anonymous
    • one year ago
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    @dan815

  2. anonymous
    • one year ago
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    @Preetha

  3. anonymous
    • one year ago
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    @pooja195

  4. anonymous
    • one year ago
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    @welshfella

  5. anonymous
    • one year ago
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    @welshfella

  6. anonymous
    • one year ago
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    i WILL MEDAL/FAN PLEASE HELP!

  7. alekos
    • one year ago
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    \[\sum_{i=1}^{n}a _{i} = a _{1}\frac{ 1-r ^{n} }{1-r }\]

  8. anonymous
    • one year ago
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    I dont understand the formula

  9. alekos
    • one year ago
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    just plug the values in the RHS and you'll get the sum

  10. alekos
    • one year ago
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    a1=6, r=-4 and n=7

  11. anonymous
    • one year ago
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    What values?

  12. anonymous
    • one year ago
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    Oh okay

  13. anonymous
    • one year ago
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    I got 19,664.4

  14. anonymous
    • one year ago
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    ans is -19662

  15. anonymous
    • one year ago
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    How did u get that?

  16. anonymous
    • one year ago
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    @AHSHAJHASJDHS ur ans is wrong,,,,according to me...

  17. alekos
    • one year ago
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    no your both wrong

  18. anonymous
    • one year ago
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    ok wait i am expplaining

  19. anonymous
    • one year ago
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    Can you help me get to the right answer? Mine didnt even match

  20. alekos
    • one year ago
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    \[6 \frac{ 1-(-4)^{7} }{1-(-4)}\]

  21. alekos
    • one year ago
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    this is what you need to calculate

  22. anonymous
    • one year ago
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    I got 19,662

  23. anonymous
    • one year ago
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    (6) 16385 ------- = 3277 (6) = 19662 5

  24. anonymous
    • one year ago
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    Is that right?

  25. anonymous
    • one year ago
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  26. alekos
    • one year ago
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    Yep, thats it

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