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anonymous
 one year ago
What is the probability of rolling a 6sided die two times and getting a 3 and then a 2?
anonymous
 one year ago
What is the probability of rolling a 6sided die two times and getting a 3 and then a 2?

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1The two events are independent of each other. That means that the outcome of the first roll does not influence the outcome of the second roll. That being the case, the probability of rolling a 3 followed by a 2 is the product of the two individual probabilities. p(3 then 2) = p(3) * p(2)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1What is the probability if rolling a 3? What is the probability of rolling a 2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A. 1/3 B. 1/36 C. 1/6 D. 1/18

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1I see the choices. Can you answer my questions above?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1A die has 6 possible outcomes. All 6 outcomes are equally likely. What is the probability of rolling one specific outcome out of the 6?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i wouldnt know sir/mam, that why im asking you guys for the answer

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1The idea with OS is to get help, I agree, but it is also to make you understand the material and not to just be told answers. We need to think this together and figure it out.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Let me give an example with a simpler case. You have a coin. The coin can fall with the heads side up or with the tails side up. There are only two possible outcomes with the flipping of a coin. If I flip the coin, what is the probability it will be a heads?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1In this case, the probability would be 1/2. You are correct. In your case it is 1/6.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Right. For the die, any one specific outcome is 1/6.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1This is not the final answer.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1No. Read below. Now go back to where I wrote this: p(3 then 2) = p(3) * p(2) p(3) = 1/6 p(2) = 1/6 The probability of rolling a 3 followed by a 2 is the probability of rolling a 3 ___multiplied___ by the probability of rolling a 2. p(3 then 2) = p(3) * p(2) = 1/6 * 1/6

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Don't add the individual probabilities. Multiply them instead.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You got it. Remember for future problems. If each event is independent of each other, then the individual probabilities multiply.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Another way of thinking of this is to find all the possible outcomes of rolling a die twice and then seeing how many are the desired outcome compared to the total number of possible outcomes.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1If you roll a die twice these are all the possible outcomes: 11, 12, 13, 14, 15, 16 21, 22, 23, 24, 25, 26 31, 32, 33, 34 ,35, 36 41, 42, 43, 44, 45, 46 51, 52, 53, 54, 55, 56 61, 62, 63, 64, 65, 66 As you can see, there are 36 possible different outcomes. You are interested in only one outcome, 32. 1 desired outcome out of 36 possible outcomes means a probability of 1/36

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha ok thats awesome. you are very helpful

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You're welcome. Thanks.
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