## anonymous one year ago HELP! Find the area between the curves. Simplify your answer integer or improper fraction. x=-2 x=3 y=10x y=x^2-11

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1. anonymous

Can we do this? and add the integrals? |dw:1436810481143:dw|

2. phi

There is some ambiguity to this question. Here is a graph

3. phi

They may mean add the two "subareas" or possibly, treat the left subarea as negative.

4. anonymous

yeah I don't know. I lose all my confidence when it comes to setting up the area and volume integrals

5. anonymous

Yeah, I've been stuck on this for a while now. A graph was not given either.

6. anonymous

I was thinking literally the area between the curves, so switch the upper and lower curve where they intersect. not sure though

7. anonymous

we've to find 5 coordinate points. then use integral.

8. IrishBoy123

$$\int_{-2}^{3} \ x^2 - 10 x - 11 \ dx$$ there cannot be more to it than that, surely?

9. anonymous

@IrishBoy123 I thought you had to switch the order of the curves if they intersect within the limits.

10. phi

if we are interested in finding the positive area between the curves (i.e. the size of the area we would paint), then we would break the integral into two regions: $\int_{-2}^{-1} x^2-11 - 10x \ dx + \int_{-1}^3 10x - x^2 +11 \ dx$

11. IrishBoy123

@peachpi i think you are absolutely right ty!