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anonymous
 one year ago
HELP! Find the area between the curves. Simplify your answer integer or improper fraction. x=2 x=3 y=10x y=x^211
anonymous
 one year ago
HELP! Find the area between the curves. Simplify your answer integer or improper fraction. x=2 x=3 y=10x y=x^211

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can we do this? and add the integrals? dw:1436810481143:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.0There is some ambiguity to this question. Here is a graph

phi
 one year ago
Best ResponseYou've already chosen the best response.0They may mean add the two "subareas" or possibly, treat the left subarea as negative.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah I don't know. I lose all my confidence when it comes to setting up the area and volume integrals

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, I've been stuck on this for a while now. A graph was not given either.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was thinking literally the area between the curves, so switch the upper and lower curve where they intersect. not sure though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we've to find 5 coordinate points. then use integral.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0\(\int_{2}^{3} \ x^2  10 x  11 \ dx\) there cannot be more to it than that, surely?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 I thought you had to switch the order of the curves if they intersect within the limits.

phi
 one year ago
Best ResponseYou've already chosen the best response.0if we are interested in finding the positive area between the curves (i.e. the size of the area we would paint), then we would break the integral into two regions: \[ \int_{2}^{1} x^211  10x \ dx + \int_{1}^3 10x  x^2 +11 \ dx \]

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0@peachpi i think you are absolutely right ty!
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