Karen wants to distract her noisy four-year-old child at a restaurant. She pulls out a bag that has 4 black marbles, 8 red marbles, and 9 green marbles. The child likes green marbles. What is the probability Karen will randomly pick a green marble from the bag in one try?

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Karen wants to distract her noisy four-year-old child at a restaurant. She pulls out a bag that has 4 black marbles, 8 red marbles, and 9 green marbles. The child likes green marbles. What is the probability Karen will randomly pick a green marble from the bag in one try?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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green marble = 9 total # of marbles = 21 set up a fraction \(\dfrac{9}{21}\) divide by 3 \(\dfrac{3}{7}\)
43 percent or 9/21 3/7
Total no.of marbles = (4+8+9) = 21 No.of green marbles = 9 therefore, P(green) = 9/21 dividing above and below by 3 we get: 3/7

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