anonymous
  • anonymous
PLEASE HELP I WILL MEDAL! What is the standard form of equation of a circle with center at (-2, -3) and passing through the point (-2, 0)? A. (x + 2)^2 + (y + 3)^2 = 9 B. (x − 2)^2 + (y − 3)^2 = 16 C. (x − 2)^2 + (y − 3)^2 = 4 D. (x + 2)^2 + (y + 3)^2 = 16 E. (x − 2)^2 + (y + 3)^2 = 9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@peachpi
anonymous
  • anonymous
@joyraheb
anonymous
  • anonymous
What's the distance between the points (-2, 0) and (-2, 3)? That distance will be the radius.

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anonymous
  • anonymous
4?
anonymous
  • anonymous
no, the x's are the same, so we can just subtract the y's. r = 0 - (-3) = 3
anonymous
  • anonymous
now just plug into the formula (x - h)² + (y - k)² = r² (h, k) is (-2, -3) the center
anonymous
  • anonymous
(x-2)^2 +(y-3)^2=9
anonymous
  • anonymous
do i switch them to addition since they were already negatives?
anonymous
  • anonymous
yes you have to switch them
anonymous
  • anonymous
so its A
anonymous
  • anonymous
yes
anonymous
  • anonymous
thank you
anonymous
  • anonymous
you're welcome

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