## anonymous one year ago What is the equation of the tangent line passing through the point (0, 3) of the graph of the function f(x) = x^2 − 2x + 3? y = –2x + 3 y = 3x + 1 y = 2x − 3 y = –3x + 3

1. Michele_Laino

here we have to apply this formula: $\Large y - 3 = f'\left( 0 \right)\left( {x - 0} \right)$

2. Michele_Laino

where f ' (0) is the first derivative of your function at point x=0