Ksp problem attached. Number 31. Thanks!

- JoannaBlackwelder

Ksp problem attached. Number 31. Thanks!

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- JoannaBlackwelder

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- JoannaBlackwelder

@taramgrant0543664 Any thoughts?

- taramgrant0543664

I wanted to work it through myself completely and I got 0.0677M As the concentration for Ag but that doesn't sound right to me

- JoannaBlackwelder

Sure, how did you get that?

- JoannaBlackwelder

I'm getting something that makes less sense, so any thoughts you have would be awesome!

- taramgrant0543664

So what I did was I took the concentration for the Ba(NO3)2 assuming since its in a 1:1 ratio the Ba2+ concentration should be the same at .5M I then used the formula Ksp=[Ba2+][CrO42-] using the Ksp for Ba (the 1.2x10^-10) and the concentration of .5M for Ba I solved for the concentration of the chromate. Having the concentration of chromate I then used the formula
[Ag2+]= sqrt(Ksp/[CrO4] where Ksp is 1.1x10^-12 and you square root it because of the stoichometric coefficients

- JoannaBlackwelder

Your method totally makes sense, thanks so much!

- taramgrant0543664

Well that's good that it makes sense lol no problem!

- JoannaBlackwelder

Oh, I have a question though. We know we can use the Ksp formula for the Ba because it tells us that it just started to precipitate. We don't know that for the Ag, so can we use that formula?

- JoannaBlackwelder

- taramgrant0543664

I never actually really considered that I just assumed since the Ksp was given

- JoannaBlackwelder

Yeah, I don't think we can use it, since we don't know if it is at the solubility point or not.

- JoannaBlackwelder

What I was thinking from here is to use the concentration of the Chromate as the concentration of the K2CrO4 in the reaction.

- JoannaBlackwelder

But that doesn't really change the concentration of the Ag+ much, so it seems strange.

- taramgrant0543664

Well we can still get up to the concentration of chromate and there is the concentration of Ag2CrO4 as .5M could you solve from there for the concentration of Ag?

- JoannaBlackwelder

I think you mean the concentration of AgNO3 is .5M, and yes, that is what I used. But it gives me the concentration of Ag+ to be essentially .5M still.

- taramgrant0543664

Haha ya that's what I mean!!! How are you setting up that equation?

- JoannaBlackwelder

Since the concentration of CrO4 is 2.4x10^-10, the concentration of K2CrO4 is the same. The molar ratio requires double the AgNO3, so 4.8x10^-10 M reacts.

- JoannaBlackwelder

Leaving .5-4.8x10^-10 = about .5M

- taramgrant0543664

Ya I'm getting the same thing... The math is alright but that answer makes no sense!

- JoannaBlackwelder

Yeah, I hear ya!

- JFraser

the problem does give the KSP for silver chromate, it is \(10^{-12}\) The KSP for silver chromate is less than the KSP for barium chromate, so the silver chromate will have already exceeded its precipitation point once the barium chromate starts to precipitate. this is clever

- taramgrant0543664

So I'm thinking since the math all seems right it's either right or it's the way I had said initially. I know it doesn't say that the precipitate formed but I looked on a solubility table and the one I looked at said that AgCrO4 is insoluble in water and makes a precipitate so could you just assume that even if it's not stated?

- JFraser

the barium chromate won't start to precipitate until most of the silver ions have precipitated, because the KSP for silver chromate is less than the KSP for barium chromate
I would find the concentration of silver in saturated silver chromate, using the KSP values and an ICE table approach, starting with the 0.5M \(AgNO_3\) That gives you the starting concentration of the silver ions once the barium ions start to precipitate. As you add more chromate ions, the silver ion concentration will continue to drop (common ion effect) until the concentration reaches the limits of the barium chromate.

- JoannaBlackwelder

So, are you saying that I can use the Ksp of the silver chromate since it will have precipitated already?

- JFraser

Id use the KSP of silver chromate to find the concentration of silver ions at the moment they start precipitating, and then compare that to the barium concentration somehow.
not exactly sure

- JFraser

I'm going to save this problem and give it to my students next year, see what we can do with it

Looking for something else?

Not the answer you are looking for? Search for more explanations.