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anonymous
 one year ago
what steps would I take to solve the problem:
Solve each equation on the interval 0<alpha<2pie
1)2sinx+sqrt2=0
2)2sin^2x3sinx+1=0
anonymous
 one year ago
what steps would I take to solve the problem: Solve each equation on the interval 0<alpha<2pie 1)2sinx+sqrt2=0 2)2sin^2x3sinx+1=0

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you mean \(0<x<2\pi\) or do you mean \(0 < \alpha < 2\pi\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But there are no alphas in your problems...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that why im confused as well lol maybe it is the first one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let's just assume that it is the first one, because that would make more sense lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, for the first one.\[2\sin(x)+\sqrt{2}=0\]\[2\sin(x)=\sqrt{2}\]\[\sin(x)=\frac{\sqrt{2}}{2}\]Now, use your trig tables to find what values of x satisfy that while making sure \(0 < x < 2\pi\). Get it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh so you pretty much want to get the sin alone

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what if there is sin and cos in the problem. ex:812sin^2x=4cos^2x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah. When solving trig equations, you want to (1) get all the trig stuff into 1 trigonometric function. So, if you have both a sine and a cosine or something, you want to (usually) get it all in terms of sine or cosine. (2) You want to solve for the trig function.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For that kind of thing, that's where you have to use your identities. For instance, in that question you just posted, trying using your pythagorean identities. \[\implies8  12\sin^2(x)=4\cos^2(x)\]\[\implies812\sin^2(x)=4(1\sin^2(x))\]\[\implies0=8\sin^2(x)4\]\[\implies\frac12=\sin^2(x)\]Does this make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ahh yes I finally understand :D thanks so much!
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