anonymous
  • anonymous
what steps would I take to solve the problem: Solve each equation on the interval 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Do you mean \(0
anonymous
  • anonymous
the 2nd one
anonymous
  • anonymous
But there are no alphas in your problems...

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anonymous
  • anonymous
that why im confused as well lol maybe it is the first one
anonymous
  • anonymous
Let's just assume that it is the first one, because that would make more sense lol
anonymous
  • anonymous
So, for the first one.\[2\sin(x)+\sqrt{2}=0\]\[2\sin(x)=-\sqrt{2}\]\[\sin(x)=-\frac{\sqrt{2}}{2}\]Now, use your trig tables to find what values of x satisfy that while making sure \(0 < x < 2\pi\). Get it?
anonymous
  • anonymous
oh so you pretty much want to get the sin alone
anonymous
  • anonymous
what if there is sin and cos in the problem. ex:8-12sin^2x=4cos^2x
anonymous
  • anonymous
Yeah. When solving trig equations, you want to (1) get all the trig stuff into 1 trigonometric function. So, if you have both a sine and a cosine or something, you want to (usually) get it all in terms of sine or cosine. (2) You want to solve for the trig function.
anonymous
  • anonymous
For that kind of thing, that's where you have to use your identities. For instance, in that question you just posted, trying using your pythagorean identities. \[\implies8 - 12\sin^2(x)=4\cos^2(x)\]\[\implies8-12\sin^2(x)=4(1-\sin^2(x))\]\[\implies0=8\sin^2(x)-4\]\[\implies\frac12=\sin^2(x)\]Does this make sense?
anonymous
  • anonymous
ahh yes I finally understand :D thanks so much!
anonymous
  • anonymous
You're welcome. :)

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