## Destinyyyy one year ago Simplify the equation. Then solve by the quadratic formula..

1. anonymous

3x^2-4x+3=0

2. freckles

$3x^2+(-4)x+3=0 \\ \text{ compare this to } \\ ax^2+bx+c=0$ what does a,b,c have to equal ?

3. anonymous

x= -(-4)+- square root (-4)^2 -4(3)(3)/2(3)

4. freckles

$a=3,b=-4,c=3 \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ x=\frac{-(-4) \pm \sqrt{(-4)^2-4(3)(3)}}{2(3)}$ is correct so far

5. freckles

-(-4)=? (-4)^2=? 4(3)(3)=? 2(3)=?

6. anonymous

4+square root 16-36/6 4+- square root -20/6

7. anonymous

Please dont talk down to me. Im in college. Im just trying to figure out where I went wrong.

8. freckles

$x=\frac{4 \pm \sqrt{16-36}}{6} \\ x=\frac{4 \pm \sqrt{-20}}{6}$ that is also correct so far

9. freckles

who is talking down to you?

10. anonymous

Any question I ask on the math group does..

11. anonymous

my example says to do this--

12. freckles

I don't know where I was talking down to you at but sorry . I will stop trying to help.

13. anonymous

6(4+-4i square root)/6 cancel out the 6

14. anonymous

Sorry I wasnt saying you were I was say please dont do what others have

15. anonymous

6(4+-4i square root 5)/6 cancel out the 6

16. anonymous

My final answer is 4+-2i square root 5 but its wrong