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Destinyyyy

  • one year ago

Simplify the equation. Then solve by the quadratic formula..

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  1. Destinyyyy
    • one year ago
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    3x^2-4x+3=0

  2. Destinyyyy
    • one year ago
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    x= -(-4)+- square root (-4)^2 -4(3)(3)/2(3)

  3. Destinyyyy
    • one year ago
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    4+square root 16-36/6 4+- square root -20/6 6(4+-4i square root 5)/6 cancel out the 6 My final answer is 4+-2i square root 5 but its wrong

  4. anonymous
    • one year ago
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    why don't you just use (4 +/- sqrt(20)i)/6

  5. Destinyyyy
    • one year ago
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    huh?? O.o

  6. zzr0ck3r
    • one year ago
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    \(3x^2-4x+3=0\implies \dfrac{-(-4)\pm \sqrt{(-4)^2-4(3)(3)}}{2(3)}=\dfrac{4\pm\sqrt{16-36}}{6}\\=\dfrac{4\pm2\sqrt{5}i}{6}=\dfrac{2\pm\sqrt{5}i}{3}\)

  7. Destinyyyy
    • one year ago
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    Sorry.. Im assuming the 2 is from 4... But im a bit confused by the rest

  8. Destinyyyy
    • one year ago
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    And shouldn't the i be before square root 5???

  9. zzr0ck3r
    • one year ago
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    the order of i does not matter, and I will show some more steps

  10. zzr0ck3r
    • one year ago
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    \(\dfrac{4\pm2\sqrt{5}i}{6}=\dfrac{2(2+\sqrt{5}i)}{2*3}=(\dfrac{2}{2})\dfrac{2+\sqrt{5}i}{3}=(\dfrac{\cancel{2}}{\cancel{2}})\dfrac{2+\sqrt{5}i}{3}=\dfrac{2\pm\sqrt{5}i}{3}=\dfrac{2\pm i\sqrt{5}}{3}\)

  11. Destinyyyy
    • one year ago
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    What is the last one??

  12. zzr0ck3r
    • one year ago
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    \(\dfrac{4\pm2\sqrt{5}i}{6}=\dfrac{2(2+\sqrt{5}i)}{2*3}=(\dfrac{2}{2})\dfrac{2+\sqrt{5}i}{3}=(\dfrac{\cancel{2}}{\cancel{2}})\dfrac{2+\sqrt{5}i}{3}=\\\dfrac{2\pm\sqrt{5}i}{3}=\dfrac{2\pm i\sqrt{5}}{3}\)

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