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anonymous
 one year ago
Please help for medal its extra credit.
Let f(x) = 5x  4 and g(x) = 6x  7. Find f(x) + g(x)
A. x  11
B. 11x  11
C. x + 3
D. 11x = 3b
anonymous
 one year ago
Please help for medal its extra credit. Let f(x) = 5x  4 and g(x) = 6x  7. Find f(x) + g(x) A. x  11 B. 11x  11 C. x + 3 D. 11x = 3b

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large {\color{red}{f(x) = 5x4}}\] \[\Large {\color{blue}{g(x) = 6x7}}\]  \[\Large {\color{red}{f(x)}} + {\color{blue}{g(x)}} = ({\color{red}{5x4}})+({\color{blue}{6x7}})\] \[\Large f(x) + g(x) = 5x4 + 6x  7\] \[\Large f(x) + g(x) = ???\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you help with another one? I dont understand the whole domain part... Let f(x) = 3x + 2 and g(x) =7x + 6. Find f ·g and its domain. A. 6x2 + 4x + 42; all real numbers B. 21x2 + 32x + 12; all real numbers C. 21x2 +32x + 12; all real numbers except x = 6/7 D. 6x2 + 4x + 42; all real numbers except x = 2/3 I know it's 21x^2+32x +12

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2f * g means f(x) times g(x) so you have to expand out (3x+2)*(7x+6) you can use the FOIL rule or a table like this one dw:1436827943285:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, I know what f(x)*g(x) is = 21x^2+32x +12 But what does it mean by find the domain? How do I find it and figure out if its all real numbers or not?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for the help (:

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2the domain of f(x) and g(x) is the set of all real numbers. You can plug in any number for x without worrying about things like division by zero, taking the square root of a negative number, etc etc. The same applies to f(x)*g(x). Multiplying any two polynomials gives you a polynomial. The domain of any polynomial is the set of all real numbers

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2saying something like `all real numbers except x = 6/7` is false because x = 6/7 is perfectly valid as an input. Go ahead and try it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I thought so! but what about f/g? f(x) = x2  16 and g(x) = x+4. Find and its domain. A. x  4; all real numbers except x not equal 4 B. x + 4; all real numbers except x not equal 4 C. x + 4; all real numbers except x not equal 4 D. x  4; all real numbers except x not equal 4; I know its Either A or D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436828284091:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2hint: you cannot divide by zero, so make sure that the denominator x+4 is not zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't quite understand..

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2solve x+4 = 0 for x to figure out what restriction you have to make

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0obviously it's 4 for x but what do you mean by restriction? I'm sorry I'm stuck.. I'm good with working through equations but this doesn't make sense to me

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2well if x = 4, then the denominator x+4 becomes 0 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you draw it out or something? How do you determine that?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2The expression simplifies to x4 The only restriction is that \(\Large x \ne 4\) to avoid making the denominator 0. Any other x value works

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh I understand now!! Thanks!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2no, I said x cannot equal 4 (not positive 4)

SetsunaYuregeshi
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910, how did you get the red and blue colors in your first posts?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2if you right click on the LaTex math, you can go to the "show math as" and then to "Tex commands"

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2strangely, it's not working for me. Idk if it's working for you but it should show you this \Large {\color{red}{f(x)}} + {\color{blue}{g(x)}} = ({\color{red}{5x4}})+({\color{blue}{6x7}})

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2surround `\Large {\color{red}{f(x)}} + {\color{blue}{g(x)}} = ({\color{red}{5x4}})+({\color{blue}{6x7}})` with `\[` and `\]` to see the LaTex formatting show up
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