Please help for medal- its extra credit. Let f(x) = -5x - 4 and g(x) = 6x - 7. Find f(x) + g(x) A. x - 11 B. -11x - 11 C. x + 3 D. -11x = 3b

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Please help for medal- its extra credit. Let f(x) = -5x - 4 and g(x) = 6x - 7. Find f(x) + g(x) A. x - 11 B. -11x - 11 C. x + 3 D. -11x = 3b

Algebra
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(-5+6)x=? -4-7=?
\[\Large {\color{red}{f(x) = -5x-4}}\] \[\Large {\color{blue}{g(x) = 6x-7}}\] -------------------------------- \[\Large {\color{red}{f(x)}} + {\color{blue}{g(x)}} = ({\color{red}{-5x-4}})+({\color{blue}{6x-7}})\] \[\Large f(x) + g(x) = -5x-4 + 6x - 7\] \[\Large f(x) + g(x) = ???\]
x-11

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correct
Can you help with another one? I dont understand the whole domain part... Let f(x) = 3x + 2 and g(x) =7x + 6. Find f ·g and its domain. A. 6x2 + 4x + 42; all real numbers B. 21x2 + 32x + 12; all real numbers C. 21x2 +32x + 12; all real numbers except x = -6/7 D. 6x2 + 4x + 42; all real numbers except x = -2/3 I know it's 21x^2+32x +12
f * g means f(x) times g(x) so you have to expand out (3x+2)*(7x+6) you can use the FOIL rule or a table like this one |dw:1436827943285:dw|
yes, I know what f(x)*g(x) is = 21x^2+32x +12 But what does it mean by find the domain? How do I find it and figure out if its all real numbers or not?
Thank you for the help (:
the domain of f(x) and g(x) is the set of all real numbers. You can plug in any number for x without worrying about things like division by zero, taking the square root of a negative number, etc etc. The same applies to f(x)*g(x). Multiplying any two polynomials gives you a polynomial. The domain of any polynomial is the set of all real numbers
saying something like `all real numbers except x = -6/7` is false because x = -6/7 is perfectly valid as an input. Go ahead and try it
I thought so! but what about f/g? f(x) = x2 - 16 and g(x) = x+4. Find and its domain. A. x - 4; all real numbers except x not equal 4 B. x + 4; all real numbers except x not equal -4 C. x + 4; all real numbers except x not equal 4 D. x - 4; all real numbers except x not equal -4; I know its Either A or D
|dw:1436828284091:dw|
hint: you cannot divide by zero, so make sure that the denominator x+4 is not zero
I don't quite understand..
solve x+4 = 0 for x to figure out what restriction you have to make
obviously it's -4 for x but what do you mean by restriction? I'm sorry I'm stuck.. I'm good with working through equations but this doesn't make sense to me
well if x = -4, then the denominator x+4 becomes 0 right?
Can you draw it out or something? How do you determine that?
I'm sorry
The expression simplifies to x-4 The only restriction is that \(\Large x \ne -4\) to avoid making the denominator 0. Any other x value works
ohh I understand now!! Thanks!
So it was A?
no, I said x cannot equal -4 (not positive 4)
oops my bad!
@jim_thompson5910, how did you get the red and blue colors in your first posts?
if you right click on the LaTex math, you can go to the "show math as" and then to "Tex commands"
strangely, it's not working for me. Idk if it's working for you but it should show you this \Large {\color{red}{f(x)}} + {\color{blue}{g(x)}} = ({\color{red}{-5x-4}})+({\color{blue}{6x-7}})
surround `\Large {\color{red}{f(x)}} + {\color{blue}{g(x)}} = ({\color{red}{-5x-4}})+({\color{blue}{6x-7}})` with `\[` and `\]` to see the LaTex formatting show up

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