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anonymous
 one year ago
Please help me, medal/fan I DONT WANT AN ANSWER
A volleyball playoff competition has eliminations each round. The table below shows the number of teams in each round of the tournament:
Round (x) 1 2 3 4
Teams f(x) 16 8 4 2
Compute the average rate of change of f(x) from x = 1 to x = 4 and identify the meaning of that rate.
anonymous
 one year ago
Please help me, medal/fan I DONT WANT AN ANSWER A volleyball playoff competition has eliminations each round. The table below shows the number of teams in each round of the tournament: Round (x) 1 2 3 4 Teams f(x) 16 8 4 2 Compute the average rate of change of f(x) from x = 1 to x = 4 and identify the meaning of that rate.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Answers: . negative three over fourteen; on average, there were 3 fewer teams every 14 rounds negative fourteen over three; on average, there were 14 fewer teams every 3 rounds 3; there were 3 rounds between rounds 1 and 4 14; there were 14 fewer team between rounds 1 and 4,

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0average rate of change from x = 1 to x = 4 average rate of change = [f(4)f(1)]/(41)

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0first step: find f(4) (what is the value of the function when x = 4?)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(4)f(1)/3 @Vocaloid

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2(1,16) and (4,2) \(\dfrac{y_2y_1}{x_2x_1}\\ y_2=2\\y_1=16\\x_2=4\\x_1=1\)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2so \(\dfrac{216}{41}\)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2what is 2  16 and 4  1 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.014 and 3 @Mehek14 sorry family dinner :(

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2ok so \(\dfrac{14}{3}\) is that in your answer choices?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, it is!! thanks!! :)
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