I will medal! Fifteen percent of the pigment in paint color A is black. Sixty percent of the pigment in paint color B is black. An unknown amount of paint color B is mixed with 40 ml of paint color A, resulting in a paint that contains 25% black pigment. Which equation can be used to solve for x, the total amount of paint in the mixture of the two colors? 0.15(40) + 0.6x = 0.25(40 + x) 0.15(40) + 0.6(x – 40) = 0.25(x) 0.15(40) + 0.6x = 0.25(40 – x) 0.15(40) + 0.6(x + 40) = 0.25(x)

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I will medal! Fifteen percent of the pigment in paint color A is black. Sixty percent of the pigment in paint color B is black. An unknown amount of paint color B is mixed with 40 ml of paint color A, resulting in a paint that contains 25% black pigment. Which equation can be used to solve for x, the total amount of paint in the mixture of the two colors? 0.15(40) + 0.6x = 0.25(40 + x) 0.15(40) + 0.6(x – 40) = 0.25(x) 0.15(40) + 0.6x = 0.25(40 – x) 0.15(40) + 0.6(x + 40) = 0.25(x)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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its A...
How'd you get A?
It should be A. :) The two terms on the left side represent the amount of black pigment with each paint color. On the right side it has the 25% in the new color combination of A (40ml) and the unknown amount (x) of B

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Thank you! :)
\[0.15(40) + 0.6x = 0.25(40 + x)\]
ur welcome... :)

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