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anonymous

  • one year ago

Help please with domain and range :) Picture attached.

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  1. anonymous
    • one year ago
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  2. ybarrap
    • one year ago
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    The term in the radical can not be negative and the denominator itself can no be zero. This implies that \(x-6 > 0\implies x>6\). This gives the domain. Note that \(x=6\) is not allowed, because that would make the denominator zero. Since the square root is always positive and all positive values close to 6 are allowed and as x gets closer to 6 the value of this function, let's call it y, approaches infinity, so \(y> 0\) is the range. Note that \(y=0\) is excluded because as x approaches infinity, y approaches zero but never reaches it. For both the domain and the range, infinity is not included at the endpoint. Domain: \((6,\infty)\) Range: \((0,\infty )\) https://www.wolframalpha.com/input/?i=plot+1%2Fsqrt%28x-6%29+%2C+6%3Cx%3Cinfinity

  3. anonymous
    • one year ago
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    thank you so much!

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